Consider the folowing combination of the 3 capacitors, where C= 3nF, C= 2nF and C,- 10nF. Knowing that the charge stored on C, is Q, 9nC, determine the charge stored on C, O Q3=10 nC O Q3=20 nC O Q3=5 nC O Q3=25nC Q3=15 nC
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- Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?4. In what form is the energy of a capacitor stored?
- You are working in an industrial plant. You have been instructed to double the capacitance connected to a machine. The markings on the capacitor, however, are not visible. The capacitor is connected to 560 volts and an ammeter indicates a current of 6 amperes flowing to the capacitor. What size capacitor should be connected in parallel with the existing capacitor? What is the minimum AC voltage rating of the new capacitor? What is the minimum DC voltage rating of the new capacitor? What is the minimum KVAR size that can be used in this installation?You are a journeyman electrician working in an industrial plant. Your task is to connect an inductor to a 480-V, 60-Hz line. To determine the proper conductor and fuse size for this installation, you need to know the amount of current the inductor will draw from the line. The nameplate on the inductor indicates that it has an inductance of 0.1 H. An ohmmeter reveals that it has a wire resistance of 10 . How much current should this inductor draw when connected to the line?Fill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5
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- The upper part of the circuit shown on the figure below consists of two parallel wires A (bluewire) and B (red wire), with following properties: Wire A: length l, resistivity ρA, cross section area SA.Wire B: length l, resistivity ρB, cross section area SB.The resistivity of the remaining (black) wires is negligible.On the right part of the circuit there is a capacitor: half of the capacitoris filled with twodielectric blocks with equal volume with dielectric constants κ1 and κ2. The other half isvacuum. The area of the capacitor plates is SC.(a) Find the equivalent RC circuit of the circuit. Deduce the time constant.(b) How much energy is stored in the capacitor in steady state?DUE IN 30 MINUTES. PLEASE ANSWER IT IN GRESA FORMAT (Given, Required, Equation, Solution, Answer). Thank you! A capacitor of 3.23µF has an area of 6.35mm^2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Prove your answerFor the arrangement shown in fig.,The values of the capacitances are C1 = 2 µF , C2= 6 µF and C3= 7 µF with a 8 V potential difference is maintained across the combination, Determine (i) Total Capacitance (ii) Charge (iii) Voltage across each capacitor (iv) Energy stored in the C1 capacitor.