Consider the function f(x) = 2x2 8х + 8, 0 < х <7. | The absolute maximum of f(x) (on the given interval) is at x = and the absolute minimum of f(x) (on the given interval) is at æ =

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.1: Graphing Quadratic Functions
Problem 4AGP
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Consider the function f(x) = 2x² – 8x + 8, 0 < x < 7.
The absolute maximum of f(x) (on the given interval) is at x =
and the absolute minimum of f(x) (on the given interval) is at x =
Transcribed Image Text:Consider the function f(x) = 2x² – 8x + 8, 0 < x < 7. The absolute maximum of f(x) (on the given interval) is at x = and the absolute minimum of f(x) (on the given interval) is at x =
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