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Advanced MathQ&A LibraryConsider the function f(x)=4sin(π2(x−3))+8. State the amplitude A, period P, and midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding x-values. Enter the exact answers. Amplitude: A= Period: P= Midline: y= The phase shift is _____ . The vertical translation is_______ Hints for the maximum and minimum values of f(x): The maximum value of y=sin(x) is y=1 and the corresponding x values are x=π2 and multiples of 2π less than and more than this x value. You may want to solve π2(x−3)=π2. The minimum value of y=sin(x) is y=−1 and the corresponding x values are x=3π2 and multiples of 2π less than and more than this x value. You may want to solve π2(x−3)=3π2. If you get a value for x that is less than 0, you could add multiples of P to get into the next cycles. If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles.Start your trial now! First week only $4.99!*arrow_forward*

Question

Consider the function f(x)=4sin(π2(x−3))+8. State the amplitude A, period P, and midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding x-values.

Enter the exact answers.

Amplitude: A=

Period: P=

Midline: y=

The phase shift is _____

.

The vertical translation is_______

Hints for the maximum and minimum values of f(x):

- The maximum value of y=sin(x) is y=1 and the corresponding x values are x=π2 and multiples of 2π less than and more than this x value. You may want to solve π2(x−3)=π2.
- The minimum value of y=sin(x) is y=−1 and the corresponding x values are x=3π2 and multiples of 2π less than and more than this x value. You may want to solve π2(x−3)=3π2.
- If you get a value for x that is less than 0, you could add multiples of P to get into the next cycles.
- If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles.

For x in the interval [0, P], the maximum y-value and corresponding x-value is at:

X=

Y=

For x in the interval [0, P], the minimum y-value and corresponding x-value is at:

X=

Y=

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