Consider the initial value problem and find the solution: a. y" + 4ay' + (4a² + 1)y = 0, b. 4y" + y' + 5y = 0, y(0) = 2, y(0) = 2, y'(0) = -3 y'(0) = 1, %3D %3D y"(0) = -1 %3D

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