Consider the initial value problem (*) y(t) 't y" + (2t+2) y' + (t + 2) y = 0 6 y(1) = = 7 - e and y'(1) = = Given that y, (t) = e-t is a solution of the differential equation, solve the initial value problem (*) 13 3 t + € 13 e Your answer should be a function of t. 8 3 - e

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