Consider the physical situation shown below. A 21.9-Newton force is applied at a 25-degree angle to the horizontal to accelerate a 5.2-kg box across a rough surface (coefficient of friction = 0.32). Use g = 9.8 m/s/s to fill in all the blanks and determine the acceleration of the box. Ffrict = a b C d a = Fnorm = N Fgrav Fapp m/s² The Normal force = 51 N The friction force = 16 N The The Normal force = 51 N The friction force = 21.9 N Normal force = 51 N The friction force = 13 N The Normal force = 42N The friction force = 13 N N N

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
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Consider the physical situation shown below. A 21.9-Newton force is applied at a 25-degree angle to the horizontal to
accelerate a 5.2-kg box across a rough surface (coefficient of friction = 0.32). Use g = 9.8 m/s/s to fill in all the blanks and
determine the acceleration of the box.
Ffrict
m
b
C
Od
=
a =
Fnorm =
Fgrav
Fapp
=
m/s²
The Normal force = 51 N The friction force = 16 N
The Normal force = 51 N The friction force = 21.9 N
The Normal force = 51 N The friction force = 13 N
The Normal force = 42N The friction force = 13 N
N
N
Transcribed Image Text:Consider the physical situation shown below. A 21.9-Newton force is applied at a 25-degree angle to the horizontal to accelerate a 5.2-kg box across a rough surface (coefficient of friction = 0.32). Use g = 9.8 m/s/s to fill in all the blanks and determine the acceleration of the box. Ffrict m b C Od = a = Fnorm = Fgrav Fapp = m/s² The Normal force = 51 N The friction force = 16 N The Normal force = 51 N The friction force = 21.9 N The Normal force = 51 N The friction force = 13 N The Normal force = 42N The friction force = 13 N N N
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