Consider the solution below to this:“Prove that if A is a set then so is {A} but do NOT use an argument that involves stages explicitly”.“Proof.” We know (NOTEs!) that, for any sets A and B, {A,B} is a set. But {A} ⊆ {A, B}, so {A} is a set by the subclass theorem.What EXACTLY is wrong with the proof above?

Given: The problem and proof statement.We need to tell what is wrong with the given proof.

Answered: Consider the solution below to this:…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Consider the solution below to this:

“Prove that if A is a set then so is {A} but do NOT use an argument that involves stages explicitly”.

“Proof.” We know (NOTEs!) that, for any sets A and B, {A,B} is a set. But {A} ⊆ {A, B}, so {A} is a set by the subclass theorem.

What EXACTLY is wrong with the proof above?

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