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Consider the structure below. Using virtual work, compute the vertical displacement at point C. 30 kN B 5 m 4 m E=200 GPa I=300(106) mmª 60 kNm

Consider the structure below. Using virtual work, compute the vertical displacement at point C. 30 kN B 5 m 4 m E=200 GPa I=300(106) mmª 60 kNm

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question 7 Consider the structure below. Using virtual work, compute the vertical displacement at point C. 30 KN B 5 m A 4 m E=200 GPa I = 300(106) mm 60 kNm
Transcribed Image Text:Question 7 Consider the structure below. Using virtual work, compute the vertical displacement at point C. 30 KN B 5 m A 4 m E=200 GPa I = 300(106) mm 60 kNm
Table for: Rectangle M M Triangle M M L Triangle M L Triangle L Trapezoid -6- slope-0 L Parabola slope - 0 L Parabola slope-0 S'MQdx L Parabola L Parabola M M M, M M slope - 0 Q Rectangle L LMQ LMQ The values in the table represent the integration of the product of the two shapes with a common length L. Triangle Triangle Trapezoid Q LMQ LMQ 2LMQ 2LMQ LMQ LMQ L LMQ LMQ LMQ 6 MQ (L + a) SLMQ (M+M) (M+2M) (2M, + M) LMQ 0 0 LMQ LMQ L LMQ LMQ 6 WE MO(L + b) LMQ LMQ 12 L LMQ LM(Q+Q) IM(Q+20) LM (2Q+Q) [Q(+b) +Q(l+a)] Q(2M,+ M) +Q (M, + 2M)] SLMQ [2(sQ+3Q) (3Q+5Q) (Q+30) M3Q+Q)
Transcribed Image Text:Table for: Rectangle M M Triangle M M L Triangle M L Triangle L Trapezoid -6- slope-0 L Parabola slope - 0 L Parabola slope-0 S'MQdx L Parabola L Parabola M M M, M M slope - 0 Q Rectangle L LMQ LMQ The values in the table represent the integration of the product of the two shapes with a common length L. Triangle Triangle Trapezoid Q LMQ LMQ 2LMQ 2LMQ LMQ LMQ L LMQ LMQ LMQ 6 MQ (L + a) SLMQ (M+M) (M+2M) (2M, + M) LMQ 0 0 LMQ LMQ L LMQ LMQ 6 WE MO(L + b) LMQ LMQ 12 L LMQ LM(Q+Q) IM(Q+20) LM (2Q+Q) [Q(+b) +Q(l+a)] Q(2M,+ M) +Q (M, + 2M)] SLMQ [2(sQ+3Q) (3Q+5Q) (Q+30) M3Q+Q)
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