Consider the system dx dy (4 – 2)(y – 2), dt = y(4 – 3x – x²) dt a) Find all the critical points (equilibrium solutions). Number of critical points: 4▼ Critical point 1: (0,0) Critical point 2: (4,0) Critical point 3: (4,0) Critical point 4: (–1,0)

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A: Solution:-dxdt=x-y+3x3-2xy2dydt=-x+y+3y3-2x2ydxdtdydt=x-y+x3x2-2y2-x+y+y3y2-2x2Hence 0,0  is…

Q: Consider the system dx dy = (4- x)(y-x), = y(4-3x - x²) dt dt a) Find all the critical points…

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Q: Find the critical points of the system mentioned in the Attachment.

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A: Critical points

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