Consider the two complex ions [Cu(CO)4]²+ and [CuCl]²¯. Choose the statements below that are true about this pair of complex ions. Choose all that apply. For [CuCl4]²- there is one unpaired electron. [Cu(CO)4]²+ absorbs light at a shorter wavelength than [CuCl4]²-. For [Cu(CO)4]²+ there are five unpaired electrons. [Cu(CO)4]²+ is high spin because carbon monoxide (CO) is a weak field ligand. [CuCl₂]² is high spin because chloride (CI) is a weak field ligand.
Consider the two complex ions [Cu(CO)4]²+ and [CuCl]²¯. Choose the statements below that are true about this pair of complex ions. Choose all that apply. For [CuCl4]²- there is one unpaired electron. [Cu(CO)4]²+ absorbs light at a shorter wavelength than [CuCl4]²-. For [Cu(CO)4]²+ there are five unpaired electrons. [Cu(CO)4]²+ is high spin because carbon monoxide (CO) is a weak field ligand. [CuCl₂]² is high spin because chloride (CI) is a weak field ligand.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter20: Chemistry Of Selected Transition Elements And Coordination Compounds
Section: Chapter Questions
Problem 45QRT
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![Consider the two complex ions [Cu(CO)4]²+ and [CuCl]²¯. Choose the
statements below that are true about this pair of complex ions. Choose
all that apply.
For [CuCl4]²- there is one unpaired electron.
[Cu(CO)4]²+ absorbs light at a shorter wavelength than [CuCl4]²-.
For [Cu(CO)4]²+ there are five unpaired electrons.
[Cu(CO)4]²+ is high spin because carbon monoxide (CO) is a weak field ligand.
[CuCl₂]² is high spin because chloride (CI) is a weak field ligand.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb006bd55-643b-4eaa-a969-1cf02688a6e8%2F8f658b1a-2409-4253-b9c3-a76b26cf81a1%2Faig237_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the two complex ions [Cu(CO)4]²+ and [CuCl]²¯. Choose the
statements below that are true about this pair of complex ions. Choose
all that apply.
For [CuCl4]²- there is one unpaired electron.
[Cu(CO)4]²+ absorbs light at a shorter wavelength than [CuCl4]²-.
For [Cu(CO)4]²+ there are five unpaired electrons.
[Cu(CO)4]²+ is high spin because carbon monoxide (CO) is a weak field ligand.
[CuCl₂]² is high spin because chloride (CI) is a weak field ligand.
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