Consider a circularly loaded flexible area on the ground surface. Given: radius of the circular area, R = 3 m; uniformly distributed load, q = 250 kN/m 2.Calculate the vertical stress increase Δσ at a point located 5 m (z) below the ground surface (immediately below the center of the circular area).

Q: Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the…

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Q: Problem 1 Refer to the soil profile in the figure below. Given H= 4m and H=3m; a) Calculate the…

A: Note : Since you have asked multiple questions, we will solve the first question for you. If you…

Q: A concentrated load of 1650 kN rests on the ground surface at coordinat Determine the net stress…

A: boussinesq theory :q=3Q2πz211+rz252 Westergaard theory :IW=Qz2π11+2rz2 32

Q: Soil Exercise The flexible area shown in Figure is uniformly loaded. Given that q = 300kN/m?…

A: Solution: Given  q=300 kN/m2 Z= 3m 8 meter wide  Vertical Pressure due t o a A line Load: σZ=…

Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…

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Q: a) determine the horizontal effective stress at A. (Ans. 53.36 kPa) b) determine the lateral…

A: For first layer,S = 30%Water Content (w) = 40%Specific Gravity of soil (GS) = 2.7For second…

Q: Calculate the effective stress at point A for the following soil profile:

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Q: Dry Sand Clay Groundwater, 4 Table 42-

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Q: Consider a circularly loaded flexible area acting on the ground surface. The radius of the circular…

A: z=10ft q=1000lb/ft2

Q: 1. A soil has the following profile and a lateral stress coefficient at rest is 0.45. 0-4 G, = 2.75…

A: Given  K0 = 0.45  Take Unit weight of water  = 10Kn/m3 Water table is at 5m below the ground…

Q: Determine the total stress, effective stress, and pore water pressure at the depth of 9.5m for the…

A: Following is the given soil profile:   Also, Assuming the specific gravity of soil, G = 2.7

Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…

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Q: Problem 3.7 For the seepage situations shown in Figure, determine the effective normal stress on…

A: Solution1By considering pore water pressure::σ'=σ-uσ=20×2+3×9.81=69.43KPau=1+39.81=39.24σ'=30.2kpaBy…

Q: Calculate the effective stress at A. 25 m Sand and- Gravel Water Table Unit Weight (y) = 20.72 kN/m…

A: Following is the given soil profile:

Q: Given in figure is soil profile where the groundwater table is 4m below the ground surface,…

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Q: Question 2/ The soil profile shown in Figure (2) subjected to downward seepage calculate the…

A: Soil subdivision can be done in many ways and there are many types of soils such as clay, dust, etc.…

Q: SITUATION. From the soil profile shown below, Ground surface Dry Sand Clay A e = 0.49 Gs=2.68 Ground…

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Q: 10.17 Refer to Figure 10.47. A flexible rectangular area is subjected to a uniformly distributed…

A: Given :

Q: with a uniform pressure of 250 kPa. a) Calculate the vertical stress increase at points A (center),…

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Q: The water table is located at a depth of 3.0 m below the ground surface in a deposit of sand 11.0 m…

A: Given: The depth of the water table below the ground surface is 3 m. The thickness of the ground…

Q: 4. A 10 m thick layer of shift, saturated clay is underlain by a layer of sand. The sand is under…

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Q: 2m Dry zone Soil properties: Gs = 2.68 A e = 0.85 В 1.8 m Saturation zone (capillary rise) 0.9 m D…

A: The soil properties are given  Specific gravity of solids, Gs = 2.68 Void ratio, e =0.85 The total…

Q: 3 m 1 m A seepage flow condition is shown in the figure. The saturated unit weight of the soil Yar…

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Q: Q3: Refer to the soil profile shown in the figure below: a) Calculate the variation in vertical…

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Q: Question 1: (10) For the soil profile shown below where H1 = 5 m and H2 = 5 m: a) Calculate the…

A: Solution   in Dry Sandrd = G1+erw = 2.681+0.6x9.81rd = 16.431 kN/m3in ClayrSat = G+e1+e rw =…

Q: A soil profile consists of a clay layer underlain by a sand layer, as shown in Figure. If a tube is…

A: From the soil mass, the pore is present that will be made by air and water. The pressure developed…

Q: A soil with a unit weight of 18 kN/m3 is loaded on the ground surface by a uniformly distributed…

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Q: 2. Soil with a unit weight of 16.50 kN/m³ is loaded on the ground surface by a uniformly distributed…

A: Determine (a) the vertical stress increment due to the uniform load,  (b) the total vertical…

Q: The sand layer shown is subjected to a downward flow of water. (52.58, 0.436, 14.36) In flow 0.70 Z…

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Q: 4. A lake with a water depth of 12m in underlain by a soil with a saturated unit weight of 18.2…

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Q: ESSES IN SOIL oblem 4. A 20m thick submerged saturated clay layer has water content of 57%. The…

A: H=20m G=2.84 w=57%

Q: ts The value of effective stress at 4 m depth for the subsoil condition as shown in figure is…

A: Given; Depth of soil Void ratio  Specific gravity of soil To find: Effective stress

Q: Qi! For the soil profile shown in the figure (1): 1- Calculate total vertical stress at the middle…

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Q: . A 5-m clay layer lies beneath an 8-m sand layer. The sand is 3 meters below the water surface.…

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Q: A soil profile is shown in Figure Q3(b)(i). The groundwater level is located on the ground surface.…

A: We are going to solve only three parts . for fourth part you have to re post this question. given…

Q: 3. | Calculate the change in total vertical normal stress (o) and in effective stress (6') au a…

A: given data: water content, w = 35% = 0.35 Depth, h = 10 ft Degree of Stauration, S = 100% Specific…

Q: A layer of sand 5 meters deep overlies a thick bed of clay. calculate the vertical, horizontal,…

A: Vertical stress is the overburden stress is a final value of the weight of rock connects a certain…

Q: Consider a circularly loaded flexible area on the ground surface. Given that the radius of the…

A: This problem is related to vertical stress topic from Soil Mechanics. In this problem there are…

Q: 9.) For linear stress variation over the base of the dam of Fig. 47, find where the resultant…

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Q: From the figure shown, H₁ = 0.60, H₂ = 0.90 m. and h = 0.45 m. The sand has a saturated unit weight…

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Q: e soil profile in the figure below. Given H= 4m and H2=3m; lculate the total stress, pore water…

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Q: A point load of 500 KN is applied at the ground level. Plot the lateral variation of the vertical…

A: Q=500kN

Q: Figure B: Stress diagram Total Stress (o) Pore Water Pressure (u) Effective Stress (o') 26.2 kPa…

A: To calculate tha pore water pressure-

Q: Problem 6 From the soil profile shown, 4.6 m Ground water table Clay e = 0.9 3.6m Gs = 2.75 1.…

A: Total stress = effective stress + neutral stress  σ = σ' + u

Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

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Q: Plot the distribution of total stress, effective stress, and pore- water pressure with depth for the…

A: Assume GS = 2.70 For unit weights: Above ground water table: Below ground water table:

Q: The area shown in the figure carries a uniform pressure of 200 kPa. Find the total vertical…

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Q: SITUATION: In accordance with Boussinesq theory, the vertical stress at a point below the center of…

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Q: Determine the value of the effective stress at the depth of 5 m in the given soil element. The…

A: Given: Specific gravity, Gs = 2.7   Soil 1 (Up to depth of 2 m): Degree of saturation, S = 0.6 Water…

Q: Calculate the effective stress at A. 25 m Sand and- Gravel Water Table Unit Weight (y) = 20.72 kN/m…

A: Given: The unit weight of water is 9.81 kN/m3. Consider the diagram,

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.