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![Exercise Precipitation titration is a volumetric method based upon the formation of
slightly soluble Precipitate:
AgNO3(aq) + NaCl(aq)
AgCl(s)
Construct a titration curve by plotting pAg vs. VAgNO3 added.
VAgNO3 (ml) [Ag"]_pAg"
0.0
5
10.0
15
20
25
30
35
40
45
50
Hints:
(a) Before equivalence point:
Ag* (aq) + C (aq)
[CI]=[NaCl] =
[Ag*] =
titrant: AgNO,, 0.IM
analyte: NaC1, 0.05M, 50 ml.
[NaCl]*V Nact-[AgNO,]*VANO,
+V AgNO,
V Naci
Ksp = 1.6* 10-10
sp
[CI]
(b) At equivalence point (moles of AgNO3 = moles of NaCl): [Ag*] =√√ksp
(c) After the equivalence point:
[Ag] =
K
[AgNO3]*V AgNO,
50+V
AgNO,
(d) pAg = -log[Ag*]
(e) Set the values of K sp, [NaC1], VNaci and [AgNO3] as reference cell.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cec4811-779c-4641-837b-c05834963975%2F16442b9b-4518-4f70-ada3-6a5b753f073d%2F9p2jwej_processed.jpeg&w=3840&q=75)
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- Solid cobalt (II) acetate is slowly added to 125 mL of 0.0945 M ammonium chromate solution. What is the concentration of cobalt required to just initiate precipitation? The Ksp of CoCrO4 is 7.1 * 10 -4. Report answer in scientific notation to two sig figs.In the standardization of NaOH with potassium hydrogen phthalate (KHP). A known amount of KHP is weighed and dissolved in water. This is then titrated incrementally with NaOH from a buret until the phenolphthalein changes color from colorless to pink. Which is the titrand? a.cannot be determined form above scenario b.HCl c.NaOH d.phenolphthalein e.KHPIn lab, you will be provided with a 1.8 M acetic acid solution (CH3COOH) and solid sodium acetate trihydrate (NaOOCCH3 3H2O). You want to make 100.0 mL of a 0.5 M acetic acid buffer at pH 5.00. How many grams of sodium acetate trihydrate, and what volume (mL) of the 1.8M acetic acid solution and deionized water should you combine? The pKa of acetic acid is 4.75. Show all work.
- Calculate the molar solubility of lead bromide, PbBr2 (Ksp = 4.0×10–5)molar solubility = Answer mol/LCalculate the pH of a saturated solution of manganese (II) hydroxide, Mn(OH)2, (Ksp = 1.9×10–13)pH = AnswerA buffer is made up of equal volumes (468.3 mL of each) of 0.860 M A H and 0.884 M A minus. 29.32 mL of 0.399 M N a O H is added to the buffer. How many moles of A minus are present after the addition of N a O H? Please use correct significant figures. Answer: (0.426) (mol)Situation: A 0.1214-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.07011 M AgNO3, the sample was back titrated with 0.06021 M KSCN, requiring 27.15 mL to reach the end point. What is the net ionic equations involved of the above titration process?