Converting to the standard normal random variable z, the probability statement P(x ≥ 43.5) is now P(z ≥ 3.90). Recall that the normal probability table gives area under the curve to the left of a given z value. Since we want the area to the right of z = 3.90 and the area under the entire curve is 1, the area to the left of z = 3.90 can be subtracted from 1. Use the table to find the probability that a student who has done their homework and attended lectures will obtain a grade of A on this test, P(z ≥ 3.90), rounding the result to four decimal places. P(z ≥ 3.90)= 1 − P(z ≤ 3.90)
Converting to the standard normal random variable z, the probability statement P(x ≥ 43.5)
is now P(z ≥ 3.90). Recall that the normal probability table gives area under the curve to the left of a given z value.
Since we want the area to the right of z = 3.90
and the area under the entire curve is 1, the area to the left of z = 3.90
can be subtracted from 1.
Use the table to find the probability that a student who has done their homework and attended lectures will obtain a grade of A on this test, P(z ≥ 3.90), rounding the result to four decimal places.
P(z ≥ 3.90)= 1 − P(z ≤ 3.90)
= 1 − ___________
= ____________
Since the percentage of students was requested, multiply this value by 100% to find the percentage of students who will obtain a grade of A on this test, rounding the result to two decimal places.
percent = 100%(probability)
= 100% (___________)
= _____________ %
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