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costs $0.07 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 6% per year? Refer to the data below. Motor A $1,100 0.74 $55 Motor B $700 0.65 Initial Cost Electrical Efficiency Annual Maintenance Life $85 5 years. 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 6% per year. The AW for Motor A is S. (Round to the nearest dollar.)

costs $0.07 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 6% per year? Refer to the data below. Motor A $1,100 0.74 $55 Motor B $700 0.65 Initial Cost Electrical Efficiency Annual Maintenance Life $85 5 years. 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 6% per year. The AW for Motor A is S. (Round to the nearest dollar.)

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
Problem 22EQ
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Two electric motors (A and B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 50 horsepower (output) to the pumping operation. It is expected that the motors will be in use 1,000 hours per year. If electricity costs $0.07 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 6% per year? Refer to the data below. Motor B Motor A $1,100 0.74 $55 Initial Cost Electrical Efficiency Annual Maintenance Life $700 0.65 $85 5 years 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 6% per year. The AW for Motor A is $. (Round to the nearest dollar.)
Transcribed Image Text:Two electric motors (A and B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 50 horsepower (output) to the pumping operation. It is expected that the motors will be in use 1,000 hours per year. If electricity costs $0.07 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 6% per year? Refer to the data below. Motor B Motor A $1,100 0.74 $55 Initial Cost Electrical Efficiency Annual Maintenance Life $700 0.65 $85 5 years 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 6% per year. The AW for Motor A is $. (Round to the nearest dollar.)
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