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Could you please write me a brief summary about the results that I have and it's about the standardization of sodium hydroxide

Could you please write me a brief summary about the results that I have and it's about the standardization of sodium hydroxide

Chemistry
Chemistry
9th Edition
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Steven S. Zumdahl
Chapter11: Properties Of Solutions
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Problem 6RQ: In terms of Raoults law, distinguish between an ideal liquid-liquid solution and a nonideal...
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Could you please write me a brief summary about the results that I have and it's about the standardization of sodium hydroxide 

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00 5. Laboratory 10: Standardization of a Sodium Hydroxide Solution Standardization of Sodium Hydroxide- Report Sheet Name Date Lab Section Hood Number Notebook /10 Technique /10 Report Sheets /80 TOTAL Standardization of a Sodium Hydroxide Solution You must show calculations for 3, 4, 5, and 7 for credit. A. Preparation of standard KHp (potassium hydrogen phthalate, KHC3H4O4) solution 9.064 1. Mass of KHp used 204.23 2. Molecular weight of KHp 0.0088 3. Moles of KHp used in 250 mL of solution 0.3414 4. Molarity of the KHp solution B. Standardization of the NaOH solution 3.25 moles Moles of KHp in 20.00 mL of KHp solution used for titration Volumes of your NaOH solution used to titrate this 20.00 mL of acid. Best two trials for each student: Your Results Partner's Results 14.30 mL 16.35 mL Trial 1 19.47 mL 13.33 mL Trial 2 MacBook Air 000 000 02 F3 DD F7 F4 F5 %23 24 4. 5. 6. 7. 6
Transcribed Image Text:00 5. Laboratory 10: Standardization of a Sodium Hydroxide Solution Standardization of Sodium Hydroxide- Report Sheet Name Date Lab Section Hood Number Notebook /10 Technique /10 Report Sheets /80 TOTAL Standardization of a Sodium Hydroxide Solution You must show calculations for 3, 4, 5, and 7 for credit. A. Preparation of standard KHp (potassium hydrogen phthalate, KHC3H4O4) solution 9.064 1. Mass of KHp used 204.23 2. Molecular weight of KHp 0.0088 3. Moles of KHp used in 250 mL of solution 0.3414 4. Molarity of the KHp solution B. Standardization of the NaOH solution 3.25 moles Moles of KHp in 20.00 mL of KHp solution used for titration Volumes of your NaOH solution used to titrate this 20.00 mL of acid. Best two trials for each student: Your Results Partner's Results 14.30 mL 16.35 mL Trial 1 19.47 mL 13.33 mL Trial 2 MacBook Air 000 000 02 F3 DD F7 F4 F5 %23 24 4. 5. 6. 7. 6
14.84 mL Best Value 6. Explain how you arrived at your best value. 0.22 7. Molarity of your NaOH solution: 6. The purposse of executing trials in quantitative analysis is to find the deviation in the results. The lesser the deviation between the values obtained in trials, the precise the result is.In the case of my result, the difference between the results obtained in Trial 1 and Trial 2 is16.35mL - 13.33mL = 3.02 mL. But in the case of my partner's result, the difference between the results obtained in Trial 1 and Trial 2 is19.47mL - 14.30 mL = 5.17 mL.There appears relatively large deviation in my partner's result. My result is better than my partner's result. The average of my result = 16.35mL + 13.33mL 216.35mL+ 13.33m / 2 = 29.68mL /2 = 14.84 mL = 14.84 mL
Transcribed Image Text:14.84 mL Best Value 6. Explain how you arrived at your best value. 0.22 7. Molarity of your NaOH solution: 6. The purposse of executing trials in quantitative analysis is to find the deviation in the results. The lesser the deviation between the values obtained in trials, the precise the result is.In the case of my result, the difference between the results obtained in Trial 1 and Trial 2 is16.35mL - 13.33mL = 3.02 mL. But in the case of my partner's result, the difference between the results obtained in Trial 1 and Trial 2 is19.47mL - 14.30 mL = 5.17 mL.There appears relatively large deviation in my partner's result. My result is better than my partner's result. The average of my result = 16.35mL + 13.33mL 216.35mL+ 13.33m / 2 = 29.68mL /2 = 14.84 mL = 14.84 mL
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