count_words(sentence): returns a dictionary with all the words in sentence in lower case as keys, and the value of each key is the number of times that word appears in a sentence. You can assume that sentences will only have letters, spaces, commas and dots.
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Implete the following function:
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- def city_dict(adict): """ Question 6 -Given a dictionary that maps a person to a list of countries they want to travel to, return a dictionary with the value being the list sorted by the last letter in each countries name. If two countries have the same last letter, sort by the first letter. -For an extra challenge, try doing this in one line (Optional). Args: adict (dict) Returns: dict >>> city_dict({"Pablo": ["Belgium", "Canada", "Germany"], "Athena": ["Italy", "France", "Egypt"], "Liv": ["Japan", "Bolivia", "Greece"]}) {'Pablo': ['Canada', 'Belgium', 'Germany'], 'Athena': ['France', 'Egypt', 'Italy'], 'Liv': ['Bolivia', 'Greece', 'Japan']} >>> city_dict({"Jacob": ["Bahamas", "Brazil", "Chile"], "Lexi": ["Colombia", "Finland", "Panama"], "Emily": ["Ireland", "Russia", "Kenya", "Jordan"]}) {'Jacob': ['Chile', 'Brazil', 'Bahamas'], 'Lexi': ['Colombia', 'Panama', 'Finland'], 'Emily': ['Kenya',…What will be displayed after the following code executes? (Note: the order of the display of entries in a dictionary are not in a specific order.)Capital QuizWrite a program that creates a dictionary containing the U.S. states as keys, and their capitals as values. (Use the Internet to get a list of the states and their capitals.) The programshould then randomly quiz the user by displaying the name of a state and asking the userto enter that state’s capital. The program should keep a count of the number of correct andincorrect responses. (As an alternative to the U.S. states, the program can use the names ofcountries and their capitals.) in phyton
- Creat a void fuction void myUpdate(string dictionary[], int wordCount, string oldWord, string newWord); Where it will replace the oldWord with the newWord, if the search is successfulMake a dictionary, the student's name is the key (a string) and the student's test scores is the value (a list). So it should be a dictionary with six key value pairs in it. Here is data to use. Brian,94,89,92 Rachel,100,90,65 Jon,67.5,95,100 Brit,0,78,80 Greg,65,100,78 Andrea,55.5,67,79 1. Now print the dictionary data using a loop that starts with for key, value in. 2. Now print the dictionary data using a loop that starts with for key in 3. Find and print out Rachels second score (should be a 90) 4. This one is a little tricky, a little mind-bender. Make a new dictionary. Using the dictionary you made from above,. the new dictionary should consist of the key is the name of the person, and the value is just the average of their scores. So it’s six key value pairs but instead of the value being a list like the first problems, this time it's just their average (which you compute from their scores in the other dictionary. Print the new dictionary out. 5. You…def get_legal_word_scores(letters, dictionary, value_dict): """ Given a str of letters that we can use, and a dictionary that contains all legal words allowed in scrabble game, and a value_dict that maps each letter to a score, Returns a dictionary that contains all possible scores earned by any legal word as the key, and for each score, the score/key maps to a list of words that are from the dictionary made from the given letters and computes to that score. The list should be in alphabetical order. """
- In pyhton Using the students dictionary provided below # This dictionary provided for youstudents = {'S1' : True,'S2' : False,'S3' : True,'S4' : False,} write a for loop that loops across the dictionary and collects all subject numbers (ex. 'S2') where the dictionary value is False. Imagine, for example, the dictionary indicates whether a student has completed an assignment, and we wanted to get a list of the students who had not yet completed the assignment. To answer this question, use a for loop across the students dictionary. You then need to get the associated value in each iteration, and check if it is True. If it is True, you can use continue to skip ahead to the next iteration. Otherwise, append the subject number (i.e. 'S2') to a list called incomplete.Which would you use to get the number of elements in a dictionary? length size sizeof lendef create_dict_from_line(header, line): """ Given the header and a single line, transform them into dictionary as described above. Header and line input are provided in this cell.
- Now do it the fixed sliding window of building a tri-gram dictionary method. You can start after 256 for the dictionary index. (a) Use window size 3 for the text: “pugonthepugonrug” (b) Think about how many of these tri-grams are used (or not used). Can you think of a way to reduce the number of tri-grams that only occur once?Write a statement that creates an empty dictionary.Correct the following code so that it correctly sets the value of each element of myList to the index of the element. int myList[10];for (int i = 1; i > 10; i++)myList[i] = i;