Create a function that takes two "sorted" arrays of numbers and returns an array of numbers which are common to both the input arrays. Examples common Elements([-1, 3, 4, 6, 7, 9], [1, 3]) [3] [1, 3, 4, 7] common Elements ([1, 3, 4, 6, 7, 9], [1, 2, 3, 4, 7, 10]) common Elements ([1, 2, 2, 2, 3, 4, 5], [1, 2, 4, 5]) → [1, 2, 4, 5] - common Elements ([1, 2, 3, 4, 5], [10, 12, 13, 15]) [] Notes Arrays are sorted. • Try doing this problem with O(n + m) time complexity. - -
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- Write a function that takes two int arrays arr1 and arr2, and their size n as parameters. The functionreturns the number of elements that exist in arr1 and arr2 with indexes i1 and i2 respectively such that i1>=i2.(Example: arr1: [ 1,5,2,3,4,0,7] arr2: [0,1,3,7,4,2] then the function returns 3 ( 0,3,7) )Please help me with this: using js create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your…2. Implement a function called findMinGap that will return the smallest gap betweenadjacent entries of an integer array. A gap between two numbers is the absolutevalue of their difference. For example, if an array contains the elements {10, 14,-5, -3, 0, 5, 7}, the minimum gap is 2 (between -5 and -3).Title line: int findMinGap(int array[], int length)
- Write a Program for insertion and deletion from an array without replacement of element from the arrays. Also, write a program to search the array for the presence of a given element from an array. Write the sub-functions in the provided test case in text form and upload the same. #include<stdio.h> #include<stdlib.h> int cmpfunc (const void * a, const void * b) { return ( *(int*)a - *(int*)b ); } int insert_function(int *data, int n, int p, int x) { /* input data: array, n: size of array, p: position of insertion, x: element to insert*/ /*output:-1 indication error or 0 if successful /* write the function for inserting element into a position*/ } int delete_function(int *data, int n, int p, int x) { /* input data: array, n: size of array, p: position of deletion, x: element to deletion*/ /*output:-1 indication error or 0 if successful /* write the function for delete element into a position*/ } int linear_search_function(int *data, int n, int x) { /*write the function to…Write a function biggest_gap(L) that takes a list L of real numbers or integers and finds the largest difference |a−b| between two adjacent elements a and b. The function should return |a−b| and the index of the second element in the list. As an example, a correctly written biggest_gap should return 25,2 when run on L=[7, 13, 38, 43, 53]. Test your function on the array A and show the result. A = [12, 45, 23, 22, 42, 15, 17, 15, 73, 36, 7, 13, 38, 43, 53, 86, 40, 45, 63, 74]Implement a function GetMinimumCutSegments(int[] arr, int k) that takes in an array arr of positive integers and an integer k, and returns the minimum number of contiguous segments of the array that must be concatenated to form an array of size k. The function should return -1 if it is not possible to create an array of size k by concatenating contiguous segments of the input array. Example: Input: [1, 2, 3, 4], 6 Output: 2 Explanation: The minimum number of contiguous segments that must be concatenated to form an array of size 6 is 2. The two segments that can be concatenated are [1, 2] and [3, 4]. Input: [1, 2, 3, 4], 7 Output: -1 Explanation: It is not possible to create an array of size 7 by concatenating contiguous segments of the input array. Constraints: The input array arr will have at most length 100. The integer k will be at least 1 and at most 10^6. Can you write a C# function that solves this problem? public int GetMinimumCutSegments(int[] arr, int k) { // Your code…
- 5. Implement the binary search function below that returns the index of the target value in an integer array. int search(int a[], int t, int l, int r); Given the binary search function in question 5 and the array a below, list all activations when calling search(a, 19, 0 15). -9 -5 -2 0 1 3 7 11 17 19 21 25 27 31 37 41 a index 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15Write a function is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4Implement a range function for a dynamic array which returns a new dynamic array that is a subset of the original. input parameters: array - (the array and any related parameters) start - index of the first elementend - index of the last elementInterval - An integer number specifying the incrementation of index This function returns a new dynamic array containing the elements from the start thru the end indices of the original array.All array indexing must be done using pointer arithmetic. For example, given the array: 49 96 99 47 76 29 22 16 30 22 If the start and end positions were 5 and 9 with step 2, return a new dynamic array: 29 16 22 Please use following main to test your function. int main(){int *p = new int[10]{49,96,99,47,76,29,22,16,30,22}; int *q = range(p,10,5,9,2);for(int i=0;i<3;i++) cout<<q[i]<<" "; // print 29 16 22 cout<<endl;delete [] q;q = range(p,10,1,8,3); for(int i=0;i<3;i++)cout<<q[i]<<" "; // print 96 76 16 cout<<endl;…
- You are given the array-like data structure Listy, which does not have a size.method. It does, however, provide an elementAt I function that returns the element at index I in the array of elements. 0( 1) time. If I exceeds the data structure's boundaries, it returns -1. (As a result, the data structure only works with positive numbers.) Given a Listy of sorted positive integer ,Determine the index at which an element x appears. If x happens more than once, you may return any index.) Write a program to overload the function call operator ( ) so as to allow the more common form of double-array subscripting. Therefore, instead of saying: chessBoard[row][column] for an array of objects, overload the function call operator to allow the alternate form: chessBoard(row, column) A sample output of your program should look like follows: chessBoard(1, 7) is 7 chessBoard(3, 5) is 15 chessBoard(8, 2) is 16 The value of each array element is the product of the row and column values. Using the class definition given in the myClassOperator.h header file below, implement the class member functions and driver code in separate files.Write a function that determines the index of the second to the last occurrence of a target b in an integer array a. Return -1 if b is not in a or there is only 1 occurrence of b in a.