e an array of size k by concatenating contiguous segments of the input array. Example: Input: [1, 2, 3, 4], 6 Output: 2 Explanation: The minimum number of contiguous segments that must be concatenated to form an array of size 6 is 2. The two segments that can be concatenated are [1, 2] and [3, 4]. Input: [1, 2, 3, 4], 7 Output: -1 Explanation: It is not possible to create an array of size 7 by concatenating contiguous segments of the input array. Constraints: The input array arr will have at most length 100. The integer k will be at least 1 and at most 10^6. Can you write a C# function that solves this problem? public int GetMinimumCutSegments(int[] arr, int k) { // Your code here }

e an array of size k by concatenating contiguous segments of the input array. Example: Input: [1, 2, 3, 4], 6 Output: 2 Explanation: The minimum number of contiguous segments that must be concatenated to form an array of size 6 is 2. The two segments that can be concatenated are [1, 2] and [3, 4]. Input: [1, 2, 3, 4], 7 Output: -1 Explanation: It is not possible to create an array of size 7 by concatenating contiguous segments of the input array. Constraints: The input array arr will have at most length 100. The integer k will be at least 1 and at most 10^6. Can you write a C# function that solves this problem? public int GetMinimumCutSegments(int[] arr, int k) { // Your code here }

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 24PE

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Write a function that gets an array of points and sorts the array using qsort(). Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)½ is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation: (1,1) is first because 12+12=2 is the smallest (3,2) is next because 32+22 = 13 is the second smallest Both (3,4) and (5,0) have the same sum of squares, 25, but 3<5 so…
Write a Python function def excludeSum(A,f) that takes as input an array of integers A and a function f that takes an integer as input and returns a boolean. excludeSum should return the sum of all the elements of A apart from those "excluded" by f, that is, those on which f returns True. For example, the following code def isOdd(n): return n%2==1 A = [2,4,1,35,42,3,3] excludeSum(A,isOdd) should return the sum of the even elements of A, i.e. 48.
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Write a program that reads an integer array a[] from the console and writes out the subsequence of the array that sums to the largest value. If there are more than one such subsequence, then the program should write out the subsequence that starts at the smallest position in the array and, if there are more than one subsequence of largest sum starting at the same smallest position, it should write out the shortest such subsequence.
Implement a C function, named median, that receives two arrays as parameters passed and returns the median of the values stored in these two arrays. The two arrays are sorted. The prototype of the function MUST be: double median(int a[], int b[], int sizeA, int sizeB);For example, if I have int a[] = {1, 2, 10, 12, 100}; and int b[] = {3, 11, 20, 500, 600}; then the median is (11+12)/2 = 11.5.
Write a program that reads an array A of N elements containing only 0's and 1's. Your program should find the position of a 0 and replace it with a 1 to get the longest continuous sequence of 1's. Let this position of 0 be called P. Print P if such a 0 exists and print -1 if the original array A contains only 1's. Assume the array indexing starts from 0.
Implement the sieve of Eratosthenes: a function for computing prime numbers, known to the ancient Greeks. Choose an integer n. This function will compute all prime numbers up to, and including, n. First insert all numbers from 1 to n into a set. Then erase all multiples of 2 (except 2); that is, 4, 6, 8, 10, 12, ... . Erase all multiples of 3, that is, 6, 9, 12, 15, ... . Go up to ?⎯⎯√n. The remaining numbers are all primes. Make sure that you use functions in your solution, including a main function. Define def sieveOfEratosthenes(n) that receives the maximum value and returns a list of all prime numbers less than or equal to this value in main() print the list of prime numbers.
In C, implement the function that gets an array of ints and its length, and returns the maximum of the absolute values. int max_abs (const int* arr, int len); For example: On input [1, -3, 7, 4] the function should return 7. On input [2, -3, 2, -4] the function should return 4. On input [0, -3, 2] the function should return 3.
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