CuCl(s) + O2g)- calculate the value of AH° for the reaction 2 F2(6) + 2 H2O → 4 HF + O2(g)-

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter7: Chemical Energy
Section: Chapter Questions
Problem 59E: In a coffee-cup calorimeter, 50.0 mL of 0.100 M AgNO3 and 50.0 mL of 0.100 M HCl are mixed to yield...
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Cu(s) + Cl2{g) → CuCl2(s).
2 Cu(s) + Cl2(g) → 2 CuCl(s)
AH° = -206 kJ
AHº = -136 kJ
From the following enthalpy changes, calculate the value of AH° for the reaction 2 F2(8) + 2 H2O → 4 HF + O2(g)-
AHo=-5 42.2 kJ
H2 (g) + F2(g) → 2 HF(g)
2 H2(g) + O2(g) → 2 H2O(1) AH° = -571.6 kJ
YeFro t Fatel → XeF4(s)-
Transcribed Image Text:Cu(s) + Cl2{g) → CuCl2(s). 2 Cu(s) + Cl2(g) → 2 CuCl(s) AH° = -206 kJ AHº = -136 kJ From the following enthalpy changes, calculate the value of AH° for the reaction 2 F2(8) + 2 H2O → 4 HF + O2(g)- AHo=-5 42.2 kJ H2 (g) + F2(g) → 2 HF(g) 2 H2(g) + O2(g) → 2 H2O(1) AH° = -571.6 kJ YeFro t Fatel → XeF4(s)-
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