(D2 + 16)y = 0

Q: 3. (D3-2D2+D-2) y=0 4. (4D3+28D²+61D+37) y=0

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Q: 2x+y 4ー dそdXdy -V4-y2

A: Triple integral is an integral of an integral with respect to three different variables. the…

Q: b. (D² – 4D + 4)y = e2x

A: problem is solved using CF and PI method

Q: c2 c4-x² xe²y 2. dy dx 4-y

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Q: Solve (D3+2D2-3D)y=x.e3x

A: Given: The given differential expression is a non-homogenous linear differential expression. The…

Q: (D5+ D4-7D³ - 11D²8D-12)y = 0

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Q: (D² +9)y=sec3x

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Q: [D³ 6D² + 11 D - 6) y = tanx -

A: Sol:- Original Differential Equation can be re-written as :- y''' -6y'' +11y' -6y=tanxThe general…

Q: (Dª + 3D³ – 6D² – 28D – 24)y = 0 -

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Q: -. (D² +4D+4)y=-x*e y =-x³e

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Q: 3t y" - y' - 6y = t²e³t - 4t², y(0) = 0, y' (0) = -1

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Q: (4D3 + D)y = e2x

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Q: (D3 + 7D2 + 19D + 13)y = 0

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Q: (D³ -3D* +4D³ -8D² +16),y = 0

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Q: d²y Find d , if you know y = 2x³ ?

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Q: (D² – 9D)(D² – 8D + 7)y = 0 |

A: We have to find the solutions of the given differential equations

Q: y = (t² – 2)². a²y = t2 dx²

A: Derivative Question

Q: Determine the solution of ( D3 - 4D2 + 3D)y = 0

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Q: Find the solution (D3 + D2 − 4D − 4)y = 8x + 8 + 6e-x

A: The given problem is to find the solution for the given non homogeneous linear differential…

Q: (D2 – 4D + 4)y = e3x

A: Given ODE is: (D2-4D+4)y=e3x

Q: (D² - 3D + 2)y = 2e¯* +8 Your answer

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Q: (D²+4D+5)y=35e : y(0)--3, y'(0)-1

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Q: [D³ – D)y = -2(1+x) + 4e* - 6e¬* + 96e3× %3D

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Q: find the solution (D^3-3D-2)y=0 when x=0, y=0 and y'=9, y''=0

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Q: 6. (D - 4D2 + 7D)y = 0 (D3

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Q: Find d2y/dx2.  y = 2/(2 + x2)

A: Given: y=22+x2

Q: (d) y" – 6y" + 11y' – 6y = e2" (5 – 4x – 3a²)

A: Given  A non homogeneous differential equation in question 2. D.

Q: +(ux+y-3) dy=D0 Q=Ap(5-人+以り)+ Xp[^ーメ2)

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Q: (D³ – 3D + 2)y = -7 у" - 9y' %3D 27

A: (1).    The given differential equation is: D3-3D+2y=-7

Q: (D² +D-1} y =0 ,when x=y=0, y'=y" = 1 , y" = -1

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Q: (D3−D2+4D−4)y=0 ; y(0)=2, y'(0)=7, y"(0)=-3

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Q: (D² +D-1)²y= 0 ,when x= y= 0, y' = y" = 1 , y" = -1

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Q: d'y Calculate dx2 y = x2

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Q: (D³ - 3D² - 6D + 8)y = xe

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Q: (D² – D – 2)y = 0 (D² + 3D)y = 0

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Q: (D² +D-1)y=0 , when x=y=0,y =y" = 1 , y" = -1

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Q: (D² – 8D + 16)y = 4e¬v2t, y(0) = -1, y'(0) = 3;

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Q: Find the solution. (D³+3D²– 4D)y = 0

A: The Auxiliary equation is D3-3D2-4D=0 solve for D D3-3D2-4D=0 DD2-3D-4=0D=0 or D2-3D-4=0 now…

Q: (D2-3D+2)y=xe*.

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Q: 2. (D5 –D – 2D³ + 18D² –31D+15)y =0

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Q: dy - 2ry = r'²

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Q: (D² – 3D – 4)y = 30e4* -

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Q: 3. Find y" y = vx² – 4 -

A: Given query is to find the derivative of the expression.

Q: (D³ + 2D*)y = 0 y(0) = -3 , y'(0) = 0 and y"(0) = 2

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Q: d*y d³y - 4· dx3 +7 d²y 14 dx4 dx2

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Q: (D'-4) y(x) = e²*

A: Given that  (D^2-4)y(x)=e^(2x)

Q: (2D* + D3-4D2 - 10D - 4)y = 0

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Q: x+y=D4 2. x-y%3D6

A: Given that, There are two equation following, x + y = 4…

Q: 3. (D3 - 4D2 + 7D)y = - 11

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Q: Obtain the solution (D³ - 2D + D – 2)y = 0

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