(D² – D – 2)y = 0 (D² + 3D)y = 0

Q: 3 y=-3 x=- √√9-y² V25– x – y’ dxdy=

A: The given problem is to evaluate the given double integral in Cartesian coordinates. We have to…

Q: Higher Order L.D.E (D2-2D+10)2y=0

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Q: (2D2 + 3D – 9)X + (D² + 7D – 14)Y = 14..... (D + 1)X + (D + 2)Y = -8e2t 1 2 唱( %3D

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Q: 2) (D² + 2D + 1) y = [exp(x) - 1]-2 %3D

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Q: D'y- 4. (4D - 4D³ - 23D2 + 12D +36)y = 0 5. (D° + 3D² + 3D + 2)y = 0 Dy +y = 0

A: The given differential equation is: (4D4-4D3-23D2+12D+36)y=0 The auxiliary equation is:…

Q: y (z² + yf) dz – a (z² – y²) dy = 0 %3D

A: Use substitution

Q: 2) (D3 + 3D2 4D – 12) y = 0 (D) (E) (F)

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Q: 3x2 +- 8(y + 1) = 0 dy y+1 C 3(: 100 - designed by freepik 24C X=Yi+(x20)

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Q: (D³ + 4D² + 9D + 10)y - 24 e*; when x = 0, y = 0, y' = -4, y" = 10. %3D

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Q: 5. (D³2D+4)y=0; y = -2, Dy = 8, D²y = 0, when x = 0.

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Q: 3. (Dª – 2D³ – 13D² + 38D – 24) = 0 4. (D² – D – 6)y = 0; when x = 0, y = 3, y' = -1 %3D

A: We have to solve the DE.

Q: %3D 0 аnd y' ) = vz 2. у(x) %3D Сisin2x + Czcos2x + 1; C1 = C2

A: Given  y(x) = C1sin2x+C2cos2x+1 On applying the initial condition yπ8 = 0 , we get yπ8 =…

Q: (D4 + 3D3 – 6D² – 28D – 24)y = 0 A. y = c;e2x + C2xe2x + C3e-3* + C4xe + C4xe-3x B. y = ce2* + c2e"…

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Q: 4. y(y² - 2x²) dx + x(2y² - x²)dy = 0 [Answer: x²y² (y² - x²) = = C

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Q: (D³– 4D°D'+ 5DD2 – 2D ) z = e'*2* + Vy + +2x +Vy +x. |

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Q: x-1² -2t d'y %3D =? y =t°-8t+1 dx 2 1= 2

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Q: 19. (D2 + 2D – 4)y = 32 %3D a. y = C1e(-1+v5x) + C2e(-1-v5x) + 8 b.y = C1e(-1+v5x) + Czol-5x) –8 c.y…

A: Let's find.

Q: 7. (D5 – 2D³ – 2D² – 3D – 2)y = 0 8. (2D3 – D² + 36D – 18)y = 0; when x = 0, y = 0, y' = 2, y" = 4

A: Note:- this is multiple questions and you have not mentioned is here which question you want to…

Q: y(t) = y" - 3y' = 8e²t - 2e-t, y(0) = 1, y'(0) = -1

A: Given

Q: d²y — 6+ 13у %3D0 dx2 dx

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Q: 3. (D2 + 2D + 1)y = 0; when x = 0, y = 1, Dy = - 1.

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Q: 2. (D³ – D)y = -2(1+x) + 4e* – 6e¬× + 96e3x

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Q: (D³ - 4D²D'+ 5DD² – 2D ) z = e'+2* + Vy+x. |

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Q: dz (D2 + 16) (D² + 4D – 5) (D² + 2D - 3)*z = 0, Dz = dr

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Q: +2x (D³ – 4D’D'+ 5DD" - 2D") z=e** + Vy +x.

A: Given PDE is D3-4D2D'+5DD'2-2D'3z=ey+2x+y+x We can write it as D-D'2D-2D'z=ey+2x+y+x             (1)…

Q: d'y if-8x-7y = 10. Find %3D dx2 Provide your answer below: -口 dy dx² FEEDBACK

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Q: (D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y" = 0. 2x y = (-2 + 3r)e¯*+2e² B В y = (-1+ 2x)e2* + 2e…

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Q: 3. D'y - D'y- Dy + y = 0 (AD4

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Q: d²y if 2x2 + 5y² = 9. Find %3D dx2 Provide your answer below: -口 dy dx2

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Q: 5. (D2 – 5D + 6)y = 18x2 + 12e2* (Assume yp = Ax² + Bx + C + Ee2x)

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Q: y"- 5y + 4y ez.

A: Use second order ordinary differential equation rules

Q: (D³ + 7D² + 19D + 13)y = 0 when x = 0,y = 0,y' = 2,y" = -12 %3D %3D

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Q: + d²z Oy2 = 0;

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Q: Find d^2 y/dx^2 in terms of x and y. y8 = x9   d^2 y/dx^2

A: Given expression is, y8=x9

Q: Evaluate (D2+3D+2)y=(1+e-x)-1

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Q: 3x+2y=D-14 x-Dy-3

A: the given system3x+2y=-14x=y-3we have to solve the system by the substitution method.

Q: (D4 + 6D3 + 9D?)y = 0 Ay = (c,+c)x+(c3+cx)e* , 3x y = c,+c,x+(cz+c,)e* y = c,+c*+ -3x D +

A: Given differential equation is (D4+6D3+9D2)y = 0

Q: d) y = - + 3 e) y = 20.5x f) y = V2(x – 6)

A: Given query is to find the transformation performed and then graph the function.

Q: y" -2y'-3y= 4e* +5, 54 d³y d²y 9. 3x %3| 3 10. . = 3e* +4x? dx? Soluc

A: In the question it is asked to solve the differential equation  y''-2y'-3y=4e3x+5…

Q: 2d²y -X dx² dx +y=(b+1)(b +2)x(In(x))

A: Given : x2d2ydx2-xdydx+y=b+1b+2xlnxb This is homogeneous linear diff. eq.

Q: d'y Calculate dx2 y = -5x2 + 7x %3D d?y dx2 %3D

A: The differentiation is a process of finding the rate of change of one variable with respect to…

Q: d²y x+2 for y=- X-3 8. Find dx2

A: Differentiate with respect to x.

Q: %3D18 SK+y%= {x-zy=9 11

A: Given query is to find the solution of the system.

Q: 23D + 12D + 36) 5. (D + 3D² + 3D + 2)y = 0 6. (D3-4D2 + 7D)y = 0 7. (D + D)y = 0 %3D

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Q: (D² – 4)y = 2 – 8x; when x = 0, y = 0, y' = 5. %3D ANS. y = e2x – e-2* + 2x – }.

A: We have to find solution of given differential equation.

Q: What is the y=x excos 2x? (A (B) (D²+5)² C D²+5 D (D²-2D+5)² D²-2D+5 annihilator for G

A: Solution

Q: d²y Find dx2 x = t* - 8, y =t – t2 %3D

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Q: D’(D² – 4)y = 3x+ 2e¬3* | y = 3x + 2e¬3x m° – 5 - 4m³ = 0 ® m' (m2 – 4) = 3x+2e-3* D (D² - 4) = 0 3…

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Q: 9. (D+3D² + 3D+1)y = 0. 13. (4D* +4D³ – 3D² - 2D + 1)y = 0.

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