D= 3 in L= 250 ft D= 2 in L= 200 ft

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter5: Stresses In Beams (basic Topics)
Section: Chapter Questions
Problem 5.5.9P: A seesaw weighing 3 lb/ft of length is occupied by two children, each weighing 90 lb (see figure)....
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If the two pipes in Fig.  are instead laid in series
with the same total pressure drop of 3 lbf/in2, what will the
flow rate be? The fluid is SAE 10 oil at 20°C.

D= 3 in
L= 250 ft
D= 2 in
L= 200 ft
Transcribed Image Text:D= 3 in L= 250 ft D= 2 in L= 200 ft
Expert Solution
Step 1

Given data:

  • The pressure drop is, ∆P = 3 lbf/in2.

Calculate the flow rate as follows:

ΔP=128μQπL1D14+L2D24

Here, Q is the flow rate, μ is the dynamic viscosity, L1 is the length of tube 1, L2 is the length of tube 2, D1 is the diameter of tube 1, and D2 is the diameter of tube 2.

Refer the table “properties of sae 10” to obtain the viscosity.

μ = 0.00217 slug/ftˑs

 

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