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Date: Period: 011: Calculate the AH for the reaction: C2H4 (g) + H2 (g) => C2H6 (g), from the following data: 1. C2H4 (g) + 302 (g) => 2 CO2 (g) + 2 H20 (1) AH - 1411 kJ / mole 2. C2 H6 (g) + 7/2 O2 (g) => 2 CO2 (g) + 3 H2O (1) AH - 1560 kJ / mole 3. H2 (g) + ½ O2 (g) => H2O (1) AH – 285.8 kJ / mole -

Date: Period: 011: Calculate the AH for the reaction: C2H4 (g) + H2 (g) => C2H6 (g), from the following data: 1. C2H4 (g) + 302 (g) => 2 CO2 (g) + 2 H20 (1) AH - 1411 kJ / mole 2. C2 H6 (g) + 7/2 O2 (g) => 2 CO2 (g) + 3 H2O (1) AH - 1560 kJ / mole 3. H2 (g) + ½ O2 (g) => H2O (1) AH – 285.8 kJ / mole -

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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Date: Period: 011: Calculate the AH for the reaction: C2H4 (g) + H2 (g) => C2H6 (g), from the following data: 1. C2H4 (g) + 302 (g) => 2 CO2 (g) + 2 H2O (1) AH-1411 kJ / mole C2 H6 (g) + 7/2 O2 (g) => 2 CO2 (g) + 3 H2O (1) AH - 1560 kJ / mole 3. H2 (g) + ½ O2 (g) => H2O (1) AH - 285.8 kJ / mole 2.
Transcribed Image Text:Date: Period: 011: Calculate the AH for the reaction: C2H4 (g) + H2 (g) => C2H6 (g), from the following data: 1. C2H4 (g) + 302 (g) => 2 CO2 (g) + 2 H2O (1) AH-1411 kJ / mole C2 H6 (g) + 7/2 O2 (g) => 2 CO2 (g) + 3 H2O (1) AH - 1560 kJ / mole 3. H2 (g) + ½ O2 (g) => H2O (1) AH - 285.8 kJ / mole 2.
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