Derive the equation of internal torques of section AB, i.e. torque for brass sleeve Tb and torque for steel shaft Ts in terms of T using the compatibility equation.
Derive the equation of internal torques of section AB, i.e. torque for brass sleeve Tb and torque for steel shaft Ts in terms of T using the compatibility equation.
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.3.15P: A hollow steel shaft used in a construction auger has an outer diameter d2= 6.0 in. and inner...
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Derive the equation of internal torques of section AB, i.e. torque for brass sleeve Tb and torque for steel shaft Ts in terms of T using the compatibility equation.
[Note: Please include the matric number and corresponding Gs value.]
![A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at end
A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gs = 40
GPa and G. = x0 GPa. The length of the assembly is L = 400 mm. The outer diameters of
the shaft and sleeve are di = 70 mm and d = 90 mm, respectively. Given the shear stress of
brass is th= 70 MPa and shear stress of steel is t,= 110 MPa.
[Note: x value - Use the last non-zero digit from your matric number. If the number is zero,
use the second last digit instead. For example, if your matric number is B051810204, your
x value is 4 and G, = 40 GPa; if your matric number is B051810090, your x value is 9 and
G, = 90 GPa.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F540793eb-a56b-4b09-8afa-5310c0bfd224%2Fd225369d-e5e9-4b9c-9999-ce842be0d2c3%2F2fgetpr_processed.png&w=3840&q=75)
Transcribed Image Text:A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at end
A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gs = 40
GPa and G. = x0 GPa. The length of the assembly is L = 400 mm. The outer diameters of
the shaft and sleeve are di = 70 mm and d = 90 mm, respectively. Given the shear stress of
brass is th= 70 MPa and shear stress of steel is t,= 110 MPa.
[Note: x value - Use the last non-zero digit from your matric number. If the number is zero,
use the second last digit instead. For example, if your matric number is B051810204, your
x value is 4 and G, = 40 GPa; if your matric number is B051810090, your x value is 9 and
G, = 90 GPa.]
Transcribed Image Text:Brass sleeve
d: = 90mm
di = 70mm
Steel shaft
T
B
I = 200mm
I- 200mm
Figure 1: A compound of shaft consisting brass sleeve and steel shaft.
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