Design a direct mapped cache with 1 MB of data and 6-word block size and assume a 33-bit address. Select the index of the cache and must keep the calculations by showing it on your designed block diagram.
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A: Address: 23D94EA616 Lines in cache: 4K Block size: 2
Design a direct mapped cache with 1 MB of data and 6-word block size and assume a 33-bit address. Select the index of the cache and must keep the calculations by showing it on your designed block diagram.
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- A 4-way set-associative cache memory unit with a capacity of 16 KB is built using a block size of 8 words. The word length is 32 bits. The size of the physical address space is 4 GB. Find the number of bits for the TAG field.A 2-way set-associative cache consists of four sets. Main memory contains 2K blocks of 8 bytes each and byte addressing is used.Q.) Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes.For a direct mapped cache with 6-word a block, 33-bit address and 18-bits index , calculate the cache entry size in bits and must keep the calculations for submission later by showing it on your designed block diagram.
- A 256 KB, direct-mapped write-back data cache with a block size of 32 Bytes is available on a computer. The cache controller receives 32-bit addresses from the CPU. In addition to the address tag, each cache tag directory entry comprises two valid bits, one modified bit, and one replacement bit. Determine the number of bits in the tag field.For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have? Tag Index Offset Block offset | Byte offset 31–12 11-6 5-2 1-0In a Direct Mapped Cache Memory Physical Address format the Cache line offset field size and word offset field size are same (with word size of one Byte). The number of tag bits in the Physical Address format is equal to the number of blocks in Cache Memory. If the Tag field Size is Mega words. 16 bits, the size of the physical Memory is
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag 31-10 Index 9-5 a. What is the cache block size (in words)? b. How many entries does the cache have? Offset 4-0 c. What is the ratio between total bits required for such a cache implementation over the data storage bits?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. a. What is the cache block size in words? b. How many entries does the cache have? Tag 31-13 Index 12-6 Offset 5-0For a direct-mapped cache with 64KİB data, 8-word blocks, and 32-bit addresses, answer the following questions: a) What is the number of blocks/lines in the cache? b) Identify the bits in the 32-bit address that are used as index bits? c) Identify the bits in the 32-bit address that are used as tag bits? d) What is the total number of bits in this cache (including tag field and valid field)? e) Identify the block number in the cache to which the following 32-bit memory address maps: Ox00003Z00 (Hexadecimal notation) where Z is the least significant digit in your student ID (written as a decimal number)
- A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.CO. A certain processor uses a fully associative cache of size 16 kB. The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index ticlds respectively in the addresses generated by the processor?The phrases "unified cache" and "Hadley cache" should be defined.