A computer has a 256 Kbyte, 4-way set associative, write back data cache with block size of 32 Bytes. The processor sends 32 bit addresses to the cache controller. Each cache tag directory entry contains, in addition to address tag, 2 valid bits, 1 modified bit and 2 replacement bit. A) Find the number of bits in the tag field of an address.

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In a certain computer, the virtual addresses are 32 bits long and the physical addresses are 48 bits long. The memory is word addressable. The page size is 16 kB and the word size is 2 bytes. The Translation Look-aside Buffer (TLB) in the address translation path has 64 valid entries. Hit ratio of TLB is 100% then maximum number of distinct virtual addresses that can be translated is K.

Assume the address format for a fully-associative cache is as follows: 6 bits 2 bits Tag Offset 8 bits Given the cache directory is as shown in the diagram below, indicate whether the memory reference Ox5E results in a cache hits or a miss. Tag valid Block 000 110110 001 000001 010 000010 011 000101 100 001000 1 101 100010 110 010111 111 110110 O Hit O Miss

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Cache system B represents a 2-way set-associative mapping cache system in table 2 The system is byte-addressable and the block size is one word (4 bytes). The tag and set numbers are represented with binary numbers. The contents of words in a block are represented with hexadecimal. Tag 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 Table 2 1. What is the size of the main memory for the Cache system B? Answer= 2. What is the size of the cache memory of Cache system B? Answer = Answer= Answer = 16 Answer = Set Number 16 1011 0110 1101 1011 0110 1101 miss(es) 1011 0110 1110 1011 0110 1110 1011 0110 1111 1011 0110 1111 1011 0111 0000 3. If we request to read memory address F1 24 2D B7, what data do we get? 1011 0111 0000 1011 0111 0001 1011 0111 0001 4. If we…

A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide. Question 1a) What is the number of cache lines? Question 1b) What is the total number of 'memory bitcells' that are needed to design this cache (note, this includes the bitcells required for the tags, valid and dirty bits).

The low order 4 bits of the address indicate location in the cache line and the next 4 bits indicate which line in the cache should be used and the remaining bits of the address are used as the cache tag. If the following addresses are read in this order, indicate (circle or similar) each one that would result in a cache miss. 2A1220 2A122C B14408 B14428 2A122C