Design. A university designs its campus with a master plan of two concentric circles. All of the academic buildings are within the inner circle (so that students can get between classes in less than 10 minutes), and the outer circle contains all the dormitories, the Greek park, cafeterias, the gymnasium, and intramural fields. Assuming the center of campus is the origin, write an equation for the inner circle if the diameter is 3000 feet. A x2-y2 1,250,000 Bx²+y2 2,250,000 (Cx2-y2 = 3,250,000 x2 + y2 = 4,250,000

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter6: Systems Of Linear Equations And Inequalities
Section6.3: Elimination Using Addition And Subtraction
Problem 44PFA
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Design. A university designs its campus with a master plan of two concentric circles. All of the academic buildings are
within the inner circle (so that students can get between classes in less than 10 minutes), and the outer circle contains all
the dormitories, the Greek park, cafeterias, the gymnasium, and intramural fields. Assuming the center of campus is the
origin, write an equation for the inner circle if the diameter is 3000 feet.
Ax-y2 1,250,000
Bx+y² = 2,250,000
x2- y2 = 3,250,000
x2 + y2 = 4,250,000
Transcribed Image Text:Design. A university designs its campus with a master plan of two concentric circles. All of the academic buildings are within the inner circle (so that students can get between classes in less than 10 minutes), and the outer circle contains all the dormitories, the Greek park, cafeterias, the gymnasium, and intramural fields. Assuming the center of campus is the origin, write an equation for the inner circle if the diameter is 3000 feet. Ax-y2 1,250,000 Bx+y² = 2,250,000 x2- y2 = 3,250,000 x2 + y2 = 4,250,000
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