DETAILS KATZPSEF1 5.P.029. 0/2 Submissions Used Two forces F₁ = (68.501 - 54.63) N and F₂ = (31.251 - 72.941) N are exerted on a particle. The particle's mass is 12.45 kg. (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a= m/s² (b) What are the magnitude and direction of the acceleration? magnitude m/s2 direction counterclockwise from the +x axis

DETAILS KATZPSEF1 5.P.029. 0/2 Submissions Used Two forces F₁ = (68.501 - 54.63) N and F₂ = (31.251 - 72.941) N are exerted on a particle. The particle's mass is 12.45 kg. (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a= m/s² (b) What are the magnitude and direction of the acceleration? magnitude m/s2 direction counterclockwise from the +x axis

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Description: Please answer the problem and give what is ask. Then show your solution and box the final answer. DETAILSTwo forces F₁ = (68.501 - 54.63) N and F₂ = (31.251 - 72.941) N are exerted on a particle. The particle's mass is 12.45 kg.(a) Find the particle'

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: The Laws Of Motion

Section: Chapter Questions

Problem 5.20CQ: Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning...

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Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The third boy in line notices that the branch is barely strong enough to support them. He decides to jump straight up and land back on the branch to break it, spilling all three into the pond. When he starts to carry out his plan, at what precise moment does the branch break? Explain. Suggestion: Pretend to be the third boy and imitate what he does in slow motion. If you are still unsure, stand on a bathroom scale and repeat the suggestion.
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A 0.51 kg football is thrown with a velocityof 18 m/s to the right. A stationary receivercatches the ball and brings it to rest in 0.020s.What is the force exerted on the receiver?Answer in units of N.
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Hi, I have this question answered with the following data: Question: A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2. Find the resultant force acting on the object. Find the magnitude of the resultant force. Given data: Given data: mass (m) = 8.00 kg, acceleration a = (4.00 î + 9.00 ĵ) m/s2 Required: The resultant force and magnitude of the resultant force According to newton's second law of motion F = ma= 8.00 kg(4.00 î + 9.00 ĵ) m/s2= (32.0 î + 72.0 ĵ) N The resultant force acting on the object is (32.0 î + 72.0 ĵ) N [can you please explain to me how do you arrived to the 78.8N] - I don't get it! Thanks The magnitude of the resultant force F = Fx2 + Fy2= 32.0 N2+72.0 N2= 78.79 N≈ 78.8 N The magnitude of the resultant force is equals to 78.8 N
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an A clarinetist, setting out for a performance, grabs his 3.390 kg clarinet case (including the clarinet) from the top of the piano and carries it through the air. At one moment, the clarinetist is applying an upward force of 41.57N Use g=9.810(m)/(s^(2)) for the acceleration due to gravity. At this moment, find the vertical component of the case's acceleration a_(y) find a_(y)=________(m)/(s^(2))