Determine a 95%-confidence interval for u.
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A: Answer:- Given a normally distributed population with mean μ = 25 and standard deviation σ = 12…
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A: Mean(μ)=21standard deviation(σ)=3.2
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A: The mean is 82 and the standard deviation is 40.
Q: A sample of 24 heads of lettuce was selected. Assume that the population distribution of head weight…
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A: Mean(μ)=63.5standard deviation(σ)=2.95sample size(n0=55
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A: Mean=M=0.22, Standard deviation=S=0.05
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A: Sample size=26
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A: For men: Mean(µ) = 69.1 Standard deviations (σ) = 2.61 For Women: Mean(µ) = 64.4Standard…
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A: Sample size n=25 Sample mean x¯=31 Population standard deviation σ=8
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A: Population = 300000 registered voters, Democrats = 30000 P(Democrats) =1 Not democrats = (300000…
Q: If n=220 and p' (p-prime) = 0.59, construct a 99% confidence interval.
A: n=220 P(prime) =0.59
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A: The regression shows the relationship b/w 1 dependent variable and 1 or more independent variables.
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A: N= 6 Mean = (sum(data)/N) Views : (X) { 30,40,70,60,80,50 } Mx = (30+...50)/6 = 55 Sales: (Y) {…
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A: From the output, the regression equation is : y = 41462 + 2714 *x here the slope = 2714
Q: Skip to Main content Question 1 Question 2 Question 3 The mean height of women in a…
A: According to the given information in this question We need to find the following probability
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A: p=0.061 n=220
Q: certain drug is used to treat asthma. In a clinical trial of the drug, 23 of 273 treated subiects…
A: Sample size n =273 Favorable cases x =23 Sample proportion p^=x/n =23/273 =0.0842 NOTE:- According…
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