in a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 12 weeks, and 15 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. The power of 0.95 shows that there is a chance of rejecting the That is, if the proportion of users who experience abdominal pain is actually the proportion of users who experience abdominal pain is than 0.08. (Type integers or decimals. Do not round.) hypothesis of p= when the true proportion is actually % chance of supporting the claim that then there is a

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 30PPS
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In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 12 weeks, and 15 subjects
experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported
with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p. the power of the test is 0.95. Interpret
this value of the power of the test.
The power of 0.95 shows that there is a % chance of rejecting the
That is, if the proportion of users who experience abdominal pain is actually
than 0.08.
the proportion of users who experience abdominal pain is
(Type integers or decimals. Do not round.)
hypothesis of p=when the true proportion is actually
% chance of supporting the claim that
then there is a
Transcribed Image Text:In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 12 weeks, and 15 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p. the power of the test is 0.95. Interpret this value of the power of the test. The power of 0.95 shows that there is a % chance of rejecting the That is, if the proportion of users who experience abdominal pain is actually than 0.08. the proportion of users who experience abdominal pain is (Type integers or decimals. Do not round.) hypothesis of p=when the true proportion is actually % chance of supporting the claim that then there is a
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