Determine reaction A (in kN, roundoff to 2 decimal places) for the loaded beam in the figure. M=105kN-m w1=70kN/m w2=40kN/m F=75kN F w1 1.8 m RA 1.8 m M 1.2 m 2.1 m RB w2 2.4 m
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- A simple beam with an overhang is subjected to d point load P = 6kN. If the maximum allowable deflect ion at point C is 0.5 mm, select the lightest W360 section from Table F-l{b) that can be used for the beam. Assume that L = 3 m and ignore the distributed weight of the beam.A simple beam AB of length L and height h (see figure) is heated in such a manner that the temperature difference 7= T{between the bottom and top of the beam is proportional to the distance from support A: that is, assume the temperature difference varies linearly along the beam: T2- Tt= Tax in which 7"0 is a constant having units of temperature (degrees) per unit distance. Determine the maximum deflection SW9Xof the beam, Repeat for a quadratic temperature variation along the beam, so T2+T1= TaxA propped cantilever beam, fixed at the left-hand end A and simply supported at the right-hand end B, is subjected to a temperature differentia] with temperature T1on its upper surface and T2on its lower surface (see figure).
- 26 - Support reactions will be found in the gerber beam whose loading condition is given in the figure. A is the fixed support, the G point is the intermediate joint, and the B support is the sliding joint. Distributed loads on the beam q1= 9 kN ⁄ m, q2= 6 kN ⁄ m, beam dimensions a = 3 m, b = 2 m. Accordingly, Bx = ?A) 19.5B) 6C) 0D) 45E) None.Given: l1=1,1l ; l2=1,9l; l3=1,4l; F1=1,5P; F2=1,5P; M=-2,5Pl. Parameter of length l=80cm; parameter of load P=1,2kN. The beam is made of steel with yielding stress σY=380MPa; factor of safety n=1,5. Find: the dimension (in mm) of cross section from strength calculation a = ? Ответ:The cantilever beam consists of a rectangular structural steel tube shape [E = 28000 ksi; I = 530 in.4]. Use double integration to determine:(a) the beam deflection vB at point B. [ Answer: vB = -.424 in](b) the beam deflection vC at point C. [ Answer: vC = -.894 in]Assume P = 12.9 kips, w = 2.7 kips/ft, LAB = 7.0 ft, LBC = 4.3 ft.
- The cantilever is subjected to a point force "P" in the middle of the beam span. The beam's modulus of elasticity, E-200 GPa and moment of inertia, l= 6x10^6 mm^4, are the same at every point. Accordingly, in which option is the maximum deflection (vertical displacement) in the beam given in "mm"? P= 12 kN, L= 2.8 m.N for Newton, m for meter, mm for millimeter, N/(mm^2) for Stress, mm^2 or m^2 for Area, mm^4 for Moment of inertia and Nm for bending moment. Use brackets if the power is MINUS for Example: 0.00125 N =1.25*10^(-3)N. A simply supported beam AB = 11 m has a hollow rectangular cross-section with 14 cm as width, 29 cm as depth and inner thickness as 1 cm is subjected to a point load of 6 N & 8 N acting at C and D respectively and a uniformly distributed load (UDL) of 8 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 2 m. Solution: i) Reaction force at B = ii) Reaction Force at A = iii) The distance from B at which the shear Force value changes from "-" to "+" = iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I = vi) Maximum bending stress = vii) Bending stress at 1 cm from…N for Newton, m for meter, mm for millimeter, N/(mm^2) for Stress, mm^2 or m^2 for Area, mm^4 for Moment of inertia and Nm for bending moment. Use brackets if the power is MINUS for Example: 0.00125 N =1.25*10^(-3)N. A simply supported beam AB = 11 m has a hollow rectangular cross-section with 14 cm as width, 29 cm as depth and inner thickness as 1 cm is subjected to a point load of 6 N & 8 N acting at C and D respectively and a uniformly distributed load (UDL) of 8 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 2 m. Solution: i) Reaction force at B = ii) Reaction Force at A = iii) The distance from B at which the shear Force value changes from "-" to "+" = Answer and unit for part 3 iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I = vi) Maximum bending stress = vii)…
- Given: l1=2l ; l2=1,9l; l3=1,7l; F1=-1,4P; F2=-2,4P; M=-0,5Pl. Parameter of length l=70cm; parameter of load P=2,2kN. The beam is made of steel with yielding stress σY=240MPa; factor of safety n=2. Find: the dimension (in mm) of cross section from strength calculation a = ?Given the following properties of a rectangular concrete beam: b = 280mm, d = 480 mm, f'c = 21 MPa, fy = 414 MPa. The beam is reinforced for tension only. Determine the design strength under the following conditions. a.) When the beam is reinforced with three 25 mm diameter bars. b.) When the beam is reinforced with four 25 mm diameter bars. c.) When the beam is reinforced with seven 25 mm diameter bars.Engineering design questions : An beam having uniform square cross section is '2' metre long supported in bearings at its ends carries a fly wheel weighing '25' kN at the centre, subjected to load which varies from 70’ N to '200' N. Determine the width and depth of a uniform square plate,. The yield strength of the materials is '850' MPa and the endurance strength '550' MPa with FOS = 2. Other correction factors may be taken as follows: For axial loading (Ka) = 0.7; For machined surface (Ksur) = 0.8 ; For size (Ksz) = 0.85 ; For stress .concentration (Kf)=1.0