A shaft madeof mild-steelupat 300 rpm. Thesupported langth of theweighingItcarriespullays each.atdistanceofImaofAssuming safe valuathe diameterof the shaft.P: 100 kwW: 1500 NS. stress: 60 MPa.= 300 rpmis required to transmit 100 kwshaft3m.is1500 N supportedfrom the ands respectively.stress as 60 MPa, determineP= 1500NP. 1500 NB->RBtwo pullaysARA3m

Answered: Image /qna-images/answer/b9df51ba-1fce-47f1-ad79-6bfe8f00670d.jpg

A shaft made of mild-steel up 3m. is required to transmit 100 kw shaft is at 300 rpm. The supported langth of the two pullays It carries zach. 1500 N supported weighing at of I'm from the ends respectively. distance a Assuming safe valua of stress as 60 MPa, determine the diameter P: 100 kw P= 1500N P: 1500N B W: 1500 N S. stress: 60 MPa. = 300 rpm of the shaft. Te Im. RA 3m. Im st RB

A shaft made of mild-steel up 3m. is required to transmit 100 kw shaft is at 300 rpm. The supported langth of the two pullays It carries zach. 1500 N supported weighing at of I'm from the ends respectively. distance a Assuming safe valua of stress as 60 MPa, determine the diameter P: 100 kw P= 1500N P: 1500N B W: 1500 N S. stress: 60 MPa. = 300 rpm of the shaft. Te Im. RA 3m. Im st RB

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

a solid shaft is transmitting 1 mw at 240 rpm determine the daimeter of shaft exceed the mean of torque 20% take maximum shear alloy stress as 55mpa
J:41) A motor delivering 3000 kW at 20 Hz to a partially hollow steel shaft (GSt=80 GPa) connected through gearing to an aluminum shaft (GAl=30 GPa) spinning a generator. The maximum shear stress in the aluminum shaft and the total angle of twist from motor to generator is: TmaxAI=6.75MPa, &tot=2.66x10^-3 radians WHY? SHOW WORK! WILL RATE
A propeller shaft for a small yacht is made ofa solid steel bar 104 mm in diameter. The allowablestress in shear is 48 MPa, and the allowable rate oftwist is 2.08 in 3.5 meters.(a) Assuming that the shear modulus of elasticityis G = 80 GPa, determine the maximum torqueTmax that can be applied to the shaft.(b) Repeat part (a) if the shaft is now hollow withan inner diameter of 5d/8. Compare Tmax valuesto corresponding values from part (a).
A steel shaft 3 m long is transmitting 1 MW at 240 rev/min. The working conditions to be satisfiedby the shaft are: (a) the shaft must not twist more than 0.02 radian on a length of 10 diameters.(b) the working stress must not exceed 60 MN/m2. If the modulus of rigidity of steel is 80 GN/m2. what is: (i) the diameter of the shaft required.(ii)the actual working stress. (iii) the angle of twist of the 3 m length.[Ans: 150 mm; 60 MN/m2 ; 0.030 rad]
A hollow steel shaft of length 1.75 m transmits 2000 kW of power at a speed of150 rev/min. The inside diameter is to be 0.75 times the outside diameter. Themaximum allowable torsional shear stress for the steel is 130 MN/m2and themodulus of rigidity (G) for the steel is 83 GN/m2. Given that a factor of safety of2 is required for the shaft, determine:i) the torque acting on the shaft;ii) the required external and internal diameters for the shaft; iii) the torsional shear stress set-up in the shaft material at the inside surfaceof the hollow shaft, and sketch the stress distribution through the shaftwall;iv) the angle of twist (in degrees) due to the torque.
A solid steel shaft ABCDE turns freely in bearings at points A and E. The shaft is driven by the gear at C,which applies a torque T2 = 325lb−ft. Gears at B and D are driven by the shaft and have resisting torquesT1 = 200lb − ft and T3 = 125lb − ft, respectively. Segments BC and CD have lengths LBC = 20 in. andLCD = 15 in. and the shear modulus G = 11, 600ksi. Determine the minimum required diameter (d) ofthe shaft if the allowable shear stress τa = 6ksi. Also calculate the angle of twist between gears B and D.
A hollow shaft has to transmit 6MW at 150rev / min. The maximum allowable stress is not to exceed 60 MN / m? nor the angle of twist 0.3 ° per meter length of shafting. If the outside diameter of the shaft is 300 mm find the minimum thickness of the hollow shaft to satisfy the above conditions. G = 80 GN / m?
A drive shaft running at 2500 rpm has outer diameter of 80mm and innerdiameter of 60mm. The allowable shear stress in the shaft is 40MPa. Determine themaximum power that can be applied.
(6) A solid shaft is used to transmit 75kW @ 550rpm. If the shaft design stress will not exceed 26N/mm2 , determine the diameter of the solid shaft.
A shaft when subjected to pure torsion developed a stress of 50 Mpa. If polar moment of inertia is 6.1359 x 10-3 m4, determine the maximum torque the shaft could handle.
The propellers of a ship are connected to an A-36 steel shaft that is 60 m long and has an outer diameter of 340 mm and inner diameter of 260 mm. If the power output is 4.5 MW when the shaft rotates at 20 rad/s, determine themaximum torsional stress in the shaft and its angle of twist.
Compute for the induced compressive stress in kPa, of a steel shafting of 59 mm diameter and 954 m in length that issubjected to an increase of temperature of 88ºC. Use 6.5x10-6/F, E = 30x106 psi.