Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. Pu + n- Xe + Zr + 3n 103 Zr + 40 94 54 Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/m Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 10° m/s 1 amu = 1 g/mol 1.66 x 10-27 kg 1 MeV = 1.60 x 10-13 J Note: mass defect = total mass of products - total mass of reactants

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter21: Nuclear Chemistry
Section: Chapter Questions
Problem 21.52QE
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Determine the change in energy (in kJ/mol) of the given nuclear fission reaction.
239 Pu +n
134
4 Xe+
54
103 Zr + 3,n
94
40
Mass of Pu-239% = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/m
%3D
Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu
Speed of light = 3.00 x 108 m/s
1 amu = 1 g/mol = 1.66 x 10-27 kg
%3D
1 MeV = 1.60 x 10-13 J
Note: mass defect = total mass of products - total mass of reactants
Transcribed Image Text:Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. 239 Pu +n 134 4 Xe+ 54 103 Zr + 3,n 94 40 Mass of Pu-239% = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/m %3D Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 108 m/s 1 amu = 1 g/mol = 1.66 x 10-27 kg %3D 1 MeV = 1.60 x 10-13 J Note: mass defect = total mass of products - total mass of reactants
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