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Determine the change in enthalpy for the following equation: Cle) +H;Oq) → 2 HClg) +1/2 O2 (3) 15. Given information: AH°r H2O = -285.8 kJ/mol AH°r H2Og = -241.8 kJ/mol AH°r HClg =-92.3 kJ/mol AH°r HClaq) = -167.2 kJ/mol AH°r O2g) = 0.00 kJ/mol AH°; Og) = 249.2 kJ/mol AH°r Clu®) = 0.00 kJ/mol AH°r Clg = 121.3 kJ/mol А. -104.5 kJ В. -470.4 kJ C. 89.3 kJ D. 101.2 kJ Е. -92.6 kJ

Determine the change in enthalpy for the following equation: Cle) +H;Oq) → 2 HClg) +1/2 O2 (3) 15. Given information: AH°r H2O = -285.8 kJ/mol AH°r H2Og = -241.8 kJ/mol AH°r HClg =-92.3 kJ/mol AH°r HClaq) = -167.2 kJ/mol AH°r O2g) = 0.00 kJ/mol AH°; Og) = 249.2 kJ/mol AH°r Clu®) = 0.00 kJ/mol AH°r Clg = 121.3 kJ/mol А. -104.5 kJ В. -470.4 kJ C. 89.3 kJ D. 101.2 kJ Е. -92.6 kJ

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 73E: Calculate the enthalpy of combustion of butane, C4H10(g) for the formation of H2O(g) and CO2(g). The...
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Determine the change in enthalpy for the following equation: Cle) +H2Oq) → 2 HClg) +1/2 O2 (3) 15. Given information: AH°r H2O = -285.8 kJ/mol AH°r H2Og) = -241.8 kJ/mol AH°r HClg) = -92.3 kJ/mol AH°r HCl(ag) = -167.2 kJ/mol AH°r O2(e) = 0.00 kJ/mol AH°r Og = 249.2 kJ/mol AH°r Cl = 0.00 kJ/mol AH° Clg) = 121.3 kJ/mol А. -104.5 kJ В. -470.4 kJ С. 89.3 kJ D. 101.2 kJ Е. -92.6 kJ
Transcribed Image Text:Determine the change in enthalpy for the following equation: Cle) +H2Oq) → 2 HClg) +1/2 O2 (3) 15. Given information: AH°r H2O = -285.8 kJ/mol AH°r H2Og) = -241.8 kJ/mol AH°r HClg) = -92.3 kJ/mol AH°r HCl(ag) = -167.2 kJ/mol AH°r O2(e) = 0.00 kJ/mol AH°r Og = 249.2 kJ/mol AH°r Cl = 0.00 kJ/mol AH° Clg) = 121.3 kJ/mol А. -104.5 kJ В. -470.4 kJ С. 89.3 kJ D. 101.2 kJ Е. -92.6 kJ
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