Determine the crystal lattice energy for MgCl2, given the following information: Mg(s) + Cl2(g) → MgCl2(s)AH°¢ = -642 kl/mol (Mg - AHvaporization = 147.7 kl/mol, Mg- - Ejonization = 2188.4 ki/mol, Cl2 - EBond = 248 kJ/mol, Cl- Ejonization = -349 kl/mol)

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter7: Chemical Bonding And Molecular Geometry
Section: Chapter Questions
Problem 84E: The lattice energy of KF is 794 kJ/mol, and the interionic distance is 269 pm. The Na—F distance in...
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Determine the crystal lattice energy for MgCl2, given the following information:
Cl2(g) → Mgčl2(s)AH°f = -642 kJ/mol
2+
(Mg - AHvaporization = 147.7 kJ/mol, Mg- Ejionization = 2188.4 kl/mol,
Cl2 - EBond = 248 kJ/mol, Cl" - Ejonization = -349 kJ/mol)
Transcribed Image Text:Determine the crystal lattice energy for MgCl2, given the following information: Cl2(g) → Mgčl2(s)AH°f = -642 kJ/mol 2+ (Mg - AHvaporization = 147.7 kJ/mol, Mg- Ejionization = 2188.4 kl/mol, Cl2 - EBond = 248 kJ/mol, Cl" - Ejonization = -349 kJ/mol)
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