Determine the equation of a circle centered at (6, 3) that has a radius of 4. (x+6)² + (y + 3)² = 4 (x-6)² + (y - 3)² = 16 (x-6)² + (y - 3)² = 4 (x+6)² + (y + 3)² = 16

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
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Chapter7: Conic Sections And Quadratic Systems
Section7.1: The Circle And The Parabola
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I have an equation of a circle problem.

Determine the equation of a circle centered at (6, 3) that has a radius of 4.
(x+6)² + (y + 3)² = 4
(x-6)² + (y - 3)² = 16
(x-6)² + (y - 3)² = 4
(x+6)² + (y + 3)² = 16
Transcribed Image Text:Determine the equation of a circle centered at (6, 3) that has a radius of 4. (x+6)² + (y + 3)² = 4 (x-6)² + (y - 3)² = 16 (x-6)² + (y - 3)² = 4 (x+6)² + (y + 3)² = 16
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