Determine the forces in members EF, BF, and BC. (By method of section) F E 12 ft 9 ft 9 ft B 3000 lb O a PEF = 2100 lb -Tension; PEF= 1500 lb – Tension; Pgc= 900 lb Tension 2100 lb-Tension; PBF= 1500 lb – Compression; Pgc= 900 lb Tension · PEF b. O C PEF = 2100 lb -Compression; Pgf= 1500 lb – Tension; PBc = 900 lb Tension PEF = 2100 lb - Compression; Pgf= 1500 lb – Compression; PBC = 900 lb Compression o d.

Structural Analysis
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Chapter2: Loads On Structures
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Determine the forces in members EFBF, and BC. (By method of section)

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Determine the forces in members EF, BF, and BC. (By method of section)
E
F
9 ft
12 ft
9 ft
D
C
3000 lb
o a. PEF = 210o lb -Tension; PRF= 1500 lb – Tension; PRC= 900 lb Tension
= 2100 lb -Tension; PBF= 1500 lb – Compression; PBC= 900 lb Tension
o b. PEF
O C. PEF = 210o lb -Compression; PBF= 1500 lb – Tension; PBc = 900 lb Tension
d.
PEF = 2100 lb - Compression; PgF= 1500 lb – Compression; PBC= 900 lb Compression
Transcribed Image Text:Determine the forces in members EF, BF, and BC. (By method of section) E F 9 ft 12 ft 9 ft D C 3000 lb o a. PEF = 210o lb -Tension; PRF= 1500 lb – Tension; PRC= 900 lb Tension = 2100 lb -Tension; PBF= 1500 lb – Compression; PBC= 900 lb Tension o b. PEF O C. PEF = 210o lb -Compression; PBF= 1500 lb – Tension; PBc = 900 lb Tension d. PEF = 2100 lb - Compression; PgF= 1500 lb – Compression; PBC= 900 lb Compression
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