Determine the number of substrings that have more s than Os. wote: A substring of a string is a sequence obtained by removing zero or more characters from elthe ont and back of the string. The substrings of string *101" are ["10r, "10", "r, "0", "or. "rz *1"° cannot me substring of "101 because it cannot be obtained by removing characters from the front or beck c xample ssumption S="011" oproech me substrings of "o" that have more s than Os are ["011,"or, "r. #, ", "r, "r, T". nerefore, the answer is 8 substrings.

EBK JAVA PROGRAMMING
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Chapter16: Graphics
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S consists of only'1' and'0'
Code snippets (also called starter code/boilerplate code)
You are given a string S that consists only of Os and is.
This question has code snippets for C, CPP, Java, and Python.
Task
Determine the number of substrings that have more is than Os.
Sample input 1
Copy
Sample output 1
Note: A substring of a string is a sequence obtained by removing zero or more characters from either/both the
2
3
front and back of the string. The substrings of string "101" are ["101", "10", "1", "O", "01", "1"} * 11" cannot be called
1010
the substring of " 101" because it cannot be obtained by removing characters from the front or back of *101".
0111
Example
Assumption
• S="0111"
Approach
The substrings of "0111" that have more 1s than Os are ["011","0111", "1", "11", "111", "1", *11", "1"}.
Explanation
Therefore, the answer is 8 substrings.
Test Case 1
Function description
S = "1010"
The substrings that have more '1' than '0' are [ "1" , "1", "101"]. Hence answer is 3.
Transcribed Image Text:More ones S consists of only'1' and'0' Code snippets (also called starter code/boilerplate code) You are given a string S that consists only of Os and is. This question has code snippets for C, CPP, Java, and Python. Task Determine the number of substrings that have more is than Os. Sample input 1 Copy Sample output 1 Note: A substring of a string is a sequence obtained by removing zero or more characters from either/both the 2 3 front and back of the string. The substrings of string "101" are ["101", "10", "1", "O", "01", "1"} * 11" cannot be called 1010 the substring of " 101" because it cannot be obtained by removing characters from the front or back of *101". 0111 Example Assumption • S="0111" Approach The substrings of "0111" that have more 1s than Os are ["011","0111", "1", "11", "111", "1", *11", "1"}. Explanation Therefore, the answer is 8 substrings. Test Case 1 Function description S = "1010" The substrings that have more '1' than '0' are [ "1" , "1", "101"]. Hence answer is 3.
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