(0.73TUNAT TI 17 016.8mH/km= 0.865 mH/km0.222Ly= 0.4605 log%3DTotal inductanceL = L, + L, = (0.627 + 0.865) mH/km = 1.492 mH/km.Example 2.20: A three phase, 50 Hz transposed transmission line has a flat horizontalconfiguration as shown in Fig. 2.30. The line reactance is 0.405 2 per kilometer. The conductorradius is 2.568 cm. Determine the phase spacing D.Solution:We knowaL = 0.4605 logbamH/km甲世

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Answered: Determine the phase spacing D.

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Electrical Engineering

Determine the phase spacing D.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

100%

(0.73
TUNAT TI 17 0
16.8
mH/km= 0.865 mH/km
0.222
Ly= 0.4605 log
%3D
Total inductance
L = L, + L, = (0.627 + 0.865) mH/km = 1.492 mH/km.
Example 2.20: A three phase, 50 Hz transposed transmission line has a flat horizontal
configuration as shown in Fig. 2.30. The line reactance is 0.405 2 per kilometer. The conductor
radius is 2.568 cm. Determine the phase spacing D.
Solution:
We know
a
L = 0.4605 log
ba
mH/km
甲
世

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