Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(g) + O2(8) [N205k (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1IN205]3 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/25-1[N205]3/2 Rate = 5.6 x 10-2 M15IN205]2

Chemistry: Matter and Change
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Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter16: Reaction Rates
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Determine the rate law and the value of k for the following reaction using the data provided.
2 N205(g) 4 NO2(8) + O2(8)
N205h (M)
Initial Rate (M/s)
0.093
4.84 x 10-4
0.174
9.05 x 10-4
0.224
1.16 x 10-3
Rate = 6.0 x 10-1 M-25-1[N20513
Rate = 1.6 x 10-3 M1/25-1[N205]1/2
Rate = 5.2 x 10-3 s[N205]
Rate = 1.7 x 10-2 M1/2s-1[N205]3/2
Rate = 5.6 x
10-2 M-151IN20512
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(8) + O2(8) N205h (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1[N20513 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/2s-1[N205]3/2 Rate = 5.6 x 10-2 M-151IN20512
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