diades/3-V169 3. Construct a sign analysis for the second derivative function and then use it to determine over what intervals (use interval notation) the CPI was speeding up and slowing down. (0042420

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
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do number 3 with the info in the previous page.

Viedz63-V11169
3. Construct a sign analysis for the second derivative function and then use it to determine over what
intervals (use interval notation) the CPI was speeding up and slowing down.
(0002420)
että fii 4 ripas lleno solzoof tool 29iqoo to 19dmun tai p9790
oral song ort nadw? --Abnemob lo visitests soha sitt britt A
SCR
b
1042
Transcribed Image Text:Viedz63-V11169 3. Construct a sign analysis for the second derivative function and then use it to determine over what intervals (use interval notation) the CPI was speeding up and slowing down. (0002420) että fii 4 ripas lleno solzoof tool 29iqoo to 19dmun tai p9790 oral song ort nadw? --Abnemob lo visitests soha sitt britt A SCR b 1042
Part III-Consumer Price Index
The U.S. Consumer Price Index (CPI) from July 2005 through March 2006 is shown below.
CPI
199.0
198.5
198.0
197.5
197.0
196.5
2
The approximating curve shown is given by the function I(t) = 0.06t3 -0.8t2+ 3.1t+ 195, 0≤t≤8,
where t is time in months and t = 0 corresponds to July 2005.
1. Use the model to compute the monthly inflation rates for December 2005 and February 2006. Show
work and include units with your answer.
your
I'W
CO.06t+C=0.86²) + C3.1+5+ (195)
IZ
dt
-0.187²-1.6++3.17 € (195) [+=5 = 0.18 (5)² -1.6(8)+3.1
I'(t) = 0.184²-1.66 +3.1
0.06050-0.8(5) ² + 3.165)+195
+²=0.18072² -1.6(7) +3.1
응
0.06 (1)-0.867)² +3.167)+195
= 4.5-8+3.1
= 0.72
7.5-20+15.5+195
198.08 €0.0036
= -0.4.
-=(-0.002
198
Inflation in February 2006
Inflation in December 2005 was
was 0.36%
-0.2%
2. Was the CPI speeding up (accelerating) or slowing down (decelerating) in February 2006? Show work.
I'"(t) = 0.18 26-1.6 The CPI was accelerating in
February 2006
= 0.366-16
I" (7) = 0.36C77-1.6
=2.52-1.6
= 0.92>0
Transcribed Image Text:Part III-Consumer Price Index The U.S. Consumer Price Index (CPI) from July 2005 through March 2006 is shown below. CPI 199.0 198.5 198.0 197.5 197.0 196.5 2 The approximating curve shown is given by the function I(t) = 0.06t3 -0.8t2+ 3.1t+ 195, 0≤t≤8, where t is time in months and t = 0 corresponds to July 2005. 1. Use the model to compute the monthly inflation rates for December 2005 and February 2006. Show work and include units with your answer. your I'W CO.06t+C=0.86²) + C3.1+5+ (195) IZ dt -0.187²-1.6++3.17 € (195) [+=5 = 0.18 (5)² -1.6(8)+3.1 I'(t) = 0.184²-1.66 +3.1 0.06050-0.8(5) ² + 3.165)+195 +²=0.18072² -1.6(7) +3.1 응 0.06 (1)-0.867)² +3.167)+195 = 4.5-8+3.1 = 0.72 7.5-20+15.5+195 198.08 €0.0036 = -0.4. -=(-0.002 198 Inflation in February 2006 Inflation in December 2005 was was 0.36% -0.2% 2. Was the CPI speeding up (accelerating) or slowing down (decelerating) in February 2006? Show work. I'"(t) = 0.18 26-1.6 The CPI was accelerating in February 2006 = 0.366-16 I" (7) = 0.36C77-1.6 =2.52-1.6 = 0.92>0
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