Dilution Experiment Test tube Starch concentration (/mL) Dilution factor Observation 1 500 1:10 Dark blue 2 50 1:100 Light blue 3 5 1:1000 Light purple 4 0.5 1:10000 Yellow 5 0.05 1:100000 Light yellow Observation: 1 has the highest concentration of starch and the following sample which are test tube 2, 3, 4 and 5 have lighter in colour which are light blue, purple, yellow and light yellow in colour respectively. Question: Discuss about the dilution experiment. Explain about the change in colour, the structure of the starch. Explain about iodine also. Calculation below (starch concentration).
Dilution Experiment Test tube Starch concentration (/mL) Dilution factor Observation 1 500 1:10 Dark blue 2 50 1:100 Light blue 3 5 1:1000 Light purple 4 0.5 1:10000 Yellow 5 0.05 1:100000 Light yellow Observation: 1 has the highest concentration of starch and the following sample which are test tube 2, 3, 4 and 5 have lighter in colour which are light blue, purple, yellow and light yellow in colour respectively. Question: Discuss about the dilution experiment. Explain about the change in colour, the structure of the starch. Explain about iodine also. Calculation below (starch concentration).
Chapter14: Formula Method
Section: Chapter Questions
Problem 34SST
Related questions
Question
Dilution Experiment
|
Test tube |
Starch concentration (/mL) |
Dilution factor |
Observation |
|
1 |
500 |
1:10 |
Dark blue |
|
2 |
50 |
1:100 |
Light blue |
|
3 |
5 |
1:1000 |
Light purple |
|
4 |
0.5 |
1:10000 |
Yellow |
|
5 |
0.05 |
1:100000 |
Light yellow |
Observation: 1 has the highest concentration of starch and the following sample which are test tube 2, 3, 4 and 5 have lighter in colour which are light blue, purple, yellow and light yellow in colour respectively.
Question: Discuss about the dilution experiment. Explain about the change in colour, the structure of the starch. Explain about iodine also. Calculation below (starch concentration).
Transcribed Image Text:Test tube 1:
(Weight / Volume) x 100 % = 0.5%
(Weight/ 1ml) x 100 % = 0.5%
Weight = 0.005g = 5mg = 500µg
X= 500µg/ml = starch concentration for test tube A
Test tube 2:
Test tube 4:
M1V1=M2V2
M1V1=M2V2
(500)(1)= M2 (10)
(5)(1)= M2 (10)
M2= 50µg/ml
M2= 0.5µg/ml
Test tube 3:
Test tube 5:
M1V1=M2V2
M1V1=M2V2
(50)(1)= M2 (10)
(0.5)(1)= M2 (10)
M2-5µg/ml
M2=0.05ug/ml
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