60,000/(i) Discuss five disadvantages of hydraulic power systems, and propose ways ofaddressing these disadvantages.(ii)-Mhandedgelt lahutuHydraulic fluids need to be oxidation resistant. Discuss this property and proposeways of reducing the levels of oxidation.(iii) Using a front end loader, 5000 kg worth of coal has to be lifted over a height of 500mm using a front end loader input cylinder with a piston of diameter 60 mm and apump force of 6.5 KN.Taking g -9.81 m/s², determine the following:(a) The multiplication of force and the diameter of the output piston.(b) The pressure in the system.veleif(c) The hydraulic power of the pump if the flow rate is at 2.6 m/s.(d) The stroke or length of movement of the input telescopic cylinder.QUESTION TWO

Hydraulic power, also known as fluid power, is energy that is delivered by the regulated circulation…

Answered: Discuss five disadvantages of hydraulic…

Discuss five disadvantages of hydraulic power systems, and propose ways of addressing these disadvantages. Hydrauli O - lig

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Explain with drawings the working principle of Hydraulic power plants.
1Two water pumps are arranged in series. The performance data for both pumps follow the parabolic curve fit Havailable =H0 =aV ^2. For pump 1, H0 =5.30 m and coefficient a =0.0438 m/Lpm^2; for pump 2, H0 =8.70 m and coefficient a =0.0347 m/Lpm^2. In either case, the units ofnet pump head H are m, and the units of capacity V are Lpm.Calculate the combined shutoff head. Complete Answer, thank you
Consider Fig. 1, the tank (with volume of 50 m3) must be filled up with water within 5 minutes. Take L1 and L2 as 5.2 m and 2.2 mrespectively: (a) determine the pumping power requirement, by assuming your own materials for the pipe of L1 and L2; (b) propose the details of the pump design (thickness of the pump etc), assuming that the pump is a vane pump while the volumetric efficiency of the pump is 0.95;
A manufacturer of small water pumps lists the performance data for a family of its pumps as a parabolic curve fit, Havailable = H0 − aV.2 , where H0 is the pump’s shutoff head and a is a coefficient. Both H0 and a are listed in a table for the pump family, along with the pump’s free delivery. The pump head is given in units of feet of water column, and capacity is given in units of gallons per minute. (a) What are the units of coefficient a? (b) Generate an expression for the pump’s ree delivery V.max in terms of H0 and a. (c) Suppose one of the manufacturer’s pumps is used to pump water from one large reservoir to another at a igher elevation. The free surfaces of both reservoirs are exposed to atmospheric pressure. The system curve simplifies to Hrequired = (z2 − z1) + bV.2 Calculate the operating point of the pump (V. operating and Hoperating) in terms of H0, a, b, and elevation difference z2 − z1.
Fixed wings with classification of 120ㅇ as illustratedis being sprayed at a flow rate of 15 m/s toThe sprayed water is 0.45 kg/s. Seek the power to action on the wings
For each statement, choose whether the statement is true or false, and discuss your answer briefly: (a) If the rpm of a pump is doubled, all else staying the same, the capacity of the pump goes up by a factor of about 2. (b) If the rpm of a pump is doubled, all else staying the same, the net head of the pump goes up by a factor of about 2. (c) If the rpm of a pump is doubled, all else staying the same, the required shaft power goes up by a factor of about 4. (d) If the rpm of a turbine is doubled, all else staying the same, the output shaft power of the turbine goes up by a factor of about 8.
Question 2 A hydro-electric power station has a reservoir area of 3,8-km2 and a capacity of 9,9 x 106 m3 . The effective head of water is 100 metres. The penstock, turbine and generation efficiencies are 95%, 90%, and 85%, respectively. 2.1 Determine the overall efficiency of the power station (%) and determine the total electrical energy that can be generated from the power station (kWh). 2.2 Determine the depth of the reservoir (metres) 2.3Determine the fall in reservoir volume level is the load of 100 kW is supplied for 5 hours (%).
The performance data of a water pump follow the curve fit Havailable = H0 = aV^2, where the pump’s shut off head H0=5.30 m, coefficient a =0.0453 m/(Lpm)^2, the units of pump head H are meters, and the units of V. are liters per minute (Lpm). The pump is used to pump water from one large reservoir to another large reservoir at a higher elevation. The free surfaces of both reservoirs are exposed to atmospheric pressure. The system curve simplifies to Hrequired =(z2- z1) + bV ^2, where elevation difference z2 =-z1 = 3.52 m,and coefficient b =0.0261 m(Lpm)^2. Calculate the operating point of the pump.
In the pump performance curve, the point at which the net head is zero is called (a) Best efficiency point (b) Free delivery (c) Shutoff head (d) Operating point (e) Duty point
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on the island, hydropower is expected to be extracted from a river of the river system via a pipe, 74 m long, to a turbine.During the dry season, from February to May the average daily flow rate of the river is 35 m3s-1 and for the remaining 8 months, the average daily flow rate of the water is 115 m3s-1. Assume, the initial capacity expenditure evaluated on a yearly basis of the run of a river system is $900 000, the annual operating cost is $17 500; and the density of water is 1000 kg ∙m-3.Considering the run of the river system above, determine(i) the energy potential at the source for one year,(ii) the levelized cost of electricity, and(iii) compare the LCOE value and the cost of electricity, and comment on the capital investment.