Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 - 5x + 2, [0, 2] Yes, it does not matter if f is continuous or differentiable, every function satifies the Mean Value Theorem. Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on R. No, f is not continuous on [0, 2]. No, f is continuous on [0, 2] but not differentiable on (0, 2). There is not enough information to verify if this function satifies the Mean Value Theorem. If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisify the hypotheses, enter DNE). C =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?
f(x) = 3x2 - 5x + 2, [0, 2]
Yes, it does not matter if f is continuous or differentiable, every function satifies the Mean Value Theorem.
Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on R.
No, f is not continuous on [0, 2].
No, f is continuous on [0, 2] but not differentiable on (0, 2).
There is not enough information to verify if this function satifies the Mean Value Theorem.
If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not
satisify the hypotheses, enter DNE).
C =
Transcribed Image Text:Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 - 5x + 2, [0, 2] Yes, it does not matter if f is continuous or differentiable, every function satifies the Mean Value Theorem. Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on R. No, f is not continuous on [0, 2]. No, f is continuous on [0, 2] but not differentiable on (0, 2). There is not enough information to verify if this function satifies the Mean Value Theorem. If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisify the hypotheses, enter DNE). C =
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