Does this answer look like I calculated correctly. The question is in a certain population of women 4% have had breast CA, 20% are smokers, and 3% are smokers and have had breast CA. A woman is selected at random from the population. What is the probability that she has had breast CA or smokes or both. 11. Do the problem #11 on page 78 in the Chapter 3 Review questions and exercisesstarting on page 76.Breast490• 04CarcerSmolkers2070o 20andBlan Sm3%.03PCA 6)= P(A)+ P(6)-P(AñA)orPCAÜB)=andPC BC or Sm or Buth)P (BC U Sm) = P(6c)+ P(Sm)- P(ocn Sa)P(,04 or ,20) = P(co4)+ P (.20)- P(.03) =and0,21So the probability that shehas had' bucst CĂ or smotesor both is 0.21

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Does this answer look like I calculated correctly. The question is in a certain population of women 4% have had breast CA, 20% are smokers, and 3% are smokers and have had breast CA. A woman is selected at random from the population. What is the probability that she has had breast CA or smokes or both.

11. Do the problem #11 on page 78 in the Chapter 3 Review questions and exercises
starting on page 76.
Breast
490
• 04
Carcer
Smolkers
2070
o 20
and
Blan Sm
3%
.03
PCA 6)= P(A)+ P(6)-P(AñA)
or
PCAÜB)=
and
PC BC or Sm or Buth)
P (BC U Sm) = P(6c)+ P(Sm)- P(ocn Sa)
P(,04 or ,20) = P(co4)+ P (.20)- P(.03) =
and
0,21
So the probability that she
has had' bucst CĂ or smotes
or both is 0.21

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