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- A manufacturer of exercise equipment knows that 15% of their products aredefective. They also know that only 35% of their customers will actually use the equipment in the first year after it is purchased. If there is a one-year warranty on the equipment, what proportion of the customers will actually make a valid warranty claim?Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…Assume that there is a 6% rate of disk filure in a year. a) If all your computer data storage is stored on a hard drive with a copy stored on a second hard disk drive, what is the probabiblity that during that year you can avoid catastrophe with at least one working drive? b) If copies of all your computer data are stored on three independent hard disk drives, what is the probablility that during a year you can avoid catastrophe with at least one working drive?
- VERYY EMERCENGYYCalculate the point prevalence for Alzheimer’s disease among individuals 65 years of age or older in a county that has 200,000 individuals who are 65 years of age or older, if 22,223 individuals who are 65 years of age or older have the disease. 0.0111 0.1111 0.8889 0.9889Male Female26,801 21,39217,251 25,0384,624 4,47927,801 18,27024,555 10,6637,767 17,11020,536 10,77916,516 19,98425,601 14,05620,948 18,51912,153 17,70311,382 11,30813,138 17,00723,568 25,14217,874 5,616102 17,63120,292 24,5689,701 16,93722,178 15,53116,189 12,88517,664 30,97022,418 6,5195,993 18,3335,899 6,10424,563 10,00311,655 17,88411,600 12,35514,317 20,13011,649 21,96117,427 13,33914,658 35,76910,205 10,68520,063 9,15415,219 11,99611,846 30,61614,723 20,53517,184 16,2678,686 17,89917,833 20,14113,345 14,90014,770 19,1535,386 11,94719,548 16,55313,755 18,12515,959 30,23816,800 38,61218,987 24,75439,299 33,12517,677 25,55947,062 32,94627,391 20,46511,298 5,18615,815 25,02111,590 14,5586,579 15,67619,395 28,954
- VERYYY EMERCENGYYFirst and second derrivative of:Acompanysellinglicensesofnewe-commercesoftwareadvertisedthatfirmsusingthissoftware could obtain, on average during the first year, a minimum yield (in cost savings) of 20 percent on average on their software investment. To disprove the claim, we checked with 10 different firms which used the software. These firms reported the following cost-saving yields (in percent) during the first year of their operations: {17.0, 19.2, 21.5, 18.6, 22.1, 14.9, 18.4, 20.1, 19.4, 18.9}. Do we have significant evidence to show that the software company’s claim of a minimum of 20 percent in cost savings was not valid? Test using α = 0.05. Compute a 95% confidence interval for the average cost-saving yield estimate.
- We wish to demonstrate that the average time to graduate from college is affected by the students having taken AP calculus in high school. Specifically we wish to demonstrate that students who have taken AP calculus in high school gradate an average of at most 0.25 years sooner than students who have not taken AP calculus in high school. If we let μ1 demote the average time to graduate for students who have not taken AP calculus and μ2 denote the average time to graduate for students who have taken AP calculus, then select the appropriate alternative hypothesis: a. μ1-μ2 = 0 b. μ1-μ2-0.25 < 0 c. μ1-μ2-0.25>0 Please explainCompute for Coefficient of Determination New Cases New Deaths 1765 4 1097 5 891 4 959 6 937 58 1047 26 1353 9 1776 8 1952 34 1906 8 2052 11 1524 139 1453 146 1912 40 2048 137 2058 8 1895 11 2163 14 1357 69 1862 64 1783 74 2178 20 1797 54 1949 53 1581 50 1173 94 2245 95 1169 71 1849 48 2109 71 2103 80 1658 58 1583 67 1266 68 1590 55 1894 61 1941 52 1790 70 1690 52 1235 65 1345 114 1734 68 2022 26 1960 12 1928 8 1685 2 1391 7 1184 53 1744 96 1901 157 2240 239 1888 20 2288 6 1414 16 1557 22 2269 72 2651 46 2921 42 2113 29 2037 4 2067 47 1783 20 2452 15 3045 19 3439 42 3276 51 3356 5 2668 7 2886 17 3749 63 4578 87 5000 72 4899 63 5404 8 4437 11 4387 18 5290 21 7103 13 7999 30 7757 39 8019 4 5867 20 6666 47 8773 56 9838 54 9595 10 9475 11 10016 16 9296 5 6128 106Year Consumer price index 2001 0.9576707944 2001 1.043445267 2001 0.1314307172 2001 -0.2812675892 2002 0.3572771719 2002 1.086752857 2002 0.4263206673 2002 0.3137689184 2003 1.011959522 2003 0.364298725 2003 0.4900181488 2003 0.01806032147 2004 0.9028530155 2004 1.431639227 2004 0.352858151 2004 0.5977496484 2005 0.6291506466 2005 1.337269885 2005 1.216795201 2005 0.5079580088 2006 0.539083558 2006 1.692359249 2006 0.5602240896 2006 -0.8520399803 2007 1.019170385 2007 1.917329089 2007 0.2759287112 2007 1.711214555 2008 1.136773642 2008 2.195344656 2008 1.163055346 2008 -2.828529429 2009 -0.497633075 2009 1.060302337 2009 0.6790719816 2009 0.2011885888 2010 0.4014150536 2010 0.4750721517 2010 0.09325049836 2010 0.2949163207 2011 1.264822375 2011 1.743310892 2011 0.4085179843 2011 -0.1520557705 2012 0.7956386559 2012 0.8275317381 2012 0.219328148 2012 0.03604046954 2013 0.5903298758 2013…