Draw a direction field for the given differential equation. Based on the direction field, determine the behavior of y as t → ∞. If this behavior depends on the initial value of y at t = 0, describe this dependency. y' = y(y - 6)² VIV a Where a = 6. Equilibrium solutions: //// 7 y(t) = 0 and y(t) = 6. !!!!!! !!!!!!! Behavior of y(t) as to depends on initial value y(to): / / / / / / / / / / / / 1 !!!!!!!!!!!!! 117111111111 / / / / / / / / / / 1 ******* y(to) > 0: y(t)→ 6. 11111111 1 y(to) < 0: y(t) diverges from y = 0. ////// Where a = 6. Equilibrium solutions: y(t) = 0 and y(t) = 6. ******* Behavior of y(t) as t→∞ depends on initial value y(to): 11 201 y(to) > 6: y(t) diverges from y = 6. 0 < y(to) < 6:y(t) → 6. y(to) < 0: y(t) diverges from y = 0. O a

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Draw a direction field for the given differential equation. Based on the direction field, determine the behavior of y as t → ∞. If this
behavior depends on the initial value of y at t = 0, describe this dependency.
y' = y(y - 6)²
G
Where a = 6. Equilibrium solutions:
y(t) = 0 and y(t) = 6.
Behavior of y(t) ast → ∞ depends on initial value y(t):
y(to) > 0: y(t)→ 6.
y(to) < 0: y(t) diverges from y = 0.
Where a = 6. Equilibrium solutions:
y(t)
=
0 and y(t) = 6.
Behavior of y(t) as t→∞ depends on initial value y(to):
y(to) > 6: y(t) diverges from y = 6.
0 < y(to) < 6: y(t) - 6.
y(to) < 0: y(t) diverges from y = 0.
.0
N
a
11/
7
0
!!
!!!!!!!!!!!!!!
!!!!!!!!!!!!
2
1 1 1
" " "
1
",
t
t
Transcribed Image Text:Draw a direction field for the given differential equation. Based on the direction field, determine the behavior of y as t → ∞. If this behavior depends on the initial value of y at t = 0, describe this dependency. y' = y(y - 6)² G Where a = 6. Equilibrium solutions: y(t) = 0 and y(t) = 6. Behavior of y(t) ast → ∞ depends on initial value y(t): y(to) > 0: y(t)→ 6. y(to) < 0: y(t) diverges from y = 0. Where a = 6. Equilibrium solutions: y(t) = 0 and y(t) = 6. Behavior of y(t) as t→∞ depends on initial value y(to): y(to) > 6: y(t) diverges from y = 6. 0 < y(to) < 6: y(t) - 6. y(to) < 0: y(t) diverges from y = 0. .0 N a 11/ 7 0 !! !!!!!!!!!!!!!! !!!!!!!!!!!! 2 1 1 1 " " " 1 ", t t
O
a
1
11
0
17 0
2
7
""
!!!!!
****
1 1 }
Where a = 6. Equilibrium solutions:
y(t) = 0 and y(t) = 6.
Behavior of y(t) as t→ ∞ depends on initial value y(to):
y(to) > 6: y(t) diverges from y = 6.
0 < y(to) < 6: y(t) → 0.
y(to) < 0: y(t) diverges from y = 0.
Where a = 6. Equilibrium solution:
y(t) = 6.
Behavior of y(t) as t→∞ is independent of initial value y(to):
y(to)
6 for all y(to).
Transcribed Image Text:O a 1 11 0 17 0 2 7 "" !!!!! **** 1 1 } Where a = 6. Equilibrium solutions: y(t) = 0 and y(t) = 6. Behavior of y(t) as t→ ∞ depends on initial value y(to): y(to) > 6: y(t) diverges from y = 6. 0 < y(to) < 6: y(t) → 0. y(to) < 0: y(t) diverges from y = 0. Where a = 6. Equilibrium solution: y(t) = 6. Behavior of y(t) as t→∞ is independent of initial value y(to): y(to) 6 for all y(to).
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