Please could someone help me with this question? I need it to be set out like the second image, but for CaCl2 and not MgCl2. Many thanks Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to(ii)calculate the electron affinity of chlorine:DHạt= +190 kJ/molCa(g)Ca(s)2e-DHJE = +1730 kJ/molCa2* (g)+Ca(g)DHạt = +121 kJ/molCl2(g)2Cl(g)DHLE= -2184 kJ/molCa2* (g)2C1 (9)CaCl2(s)+CaCl2(s)DHF = -795 kJ/molCa(s)Cl2(g)+ Mg (g) + 2e + 2CI(g)2 x first electronaffinity(CI)= 2x-349 = -6982x AH (CI) = 2 x 122 = +244%3D%3D2+Mg (g) + 2e + Cl2 (g)since two chlorinesare involved, all theenthalpies related tochlorine are doubled24Mg (g) + 2C1 (g)second IE(Mg) = +1451Mg (g) + e+ Cl(g)as one magnesiumforms Mg2+ you mustuse the first and secondIEs of magnesium(not 2 x first IE)first IE(Mg) = +738ALH (MgCl2) = -2524%3D%3DMg(g) + Cl,(g)the lattice formationAH (Mg) = +148Mg (s) + Clalg)enthalpy of MgCl2 is|-2524 kJ mol1A;H (MgCl2)= -641MgCl2 (s)Figure 2 The Born-Haber cycle for magnesium chloride, MgCl, All enthalpiesare in kJ mol

Let us draw for Calcium chloride.

Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: RHat = +190 kJ/mol Ca(s) Ca(g) DHJ = +1730 kJ/mol 2e- Ca2* (9) + Ca(g) DHat = +121 kJ/mol Cl2(g) 2C(g) | Ca2* (g) CaCl2(s) DHLE = -2184 kJ/mol 2c(g) + DH = -795 kJ/mol Ca(s) + Cl2(g) CaCl2(s)

Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: RHat = +190 kJ/mol Ca(s) Ca(g) DHJ = +1730 kJ/mol 2e- Ca2* (9) + Ca(g) DHat = +121 kJ/mol Cl2(g) 2C(g) | Ca2* (g) CaCl2(s) DHLE = -2184 kJ/mol 2c(g) + DH = -795 kJ/mol Ca(s) + Cl2(g) CaCl2(s)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter5: Electron Configurations And The Periodic Table

Section: Chapter Questions

Problem 129QRT

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