Suppose an astronaut, travels so fast that γ = 30.00 . (a) She travels from the Earth to the nearest star system, Alpha Centauri, 4.300 light years (ly) away as measured by an Earthbound observer. How far apart are the Earth and Alpha Centauri as measured by the astronaut? (b) In terms of c , what is her velocity relative to the Earth? You may neglect the motion of the Earth relative to the Sun. ΔtAlphaCentauriEarthLoLoAt(a)At,AlphaCentauri(b)Figure 28.11 (a) The Earth-bound observer measures the proper distance between the Earth and the Alpha Centauri. (b) The astronaut observesa length contraction, since the Earth and the Alpha Centauri move relative to her ship. She can travel this shorter distance in a smaller time (herproper time) without exceeding the speed of light.

Given Data: The value of a relativistic constant is, γ=30.00 The length observed by an astronaut is,…

Answered: Δt Alpha Centauri Earth Lo Lo At (a)…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter28: Special Relativity

Section: Chapter Questions

Problem 19CQ: The mass of the fuel in a nuclear reactor decreases by an observable amount as it puts out energy....

See similar textbooks

Related questions

Question

Suppose an astronaut, travels so fast that γ = 30.00 .

(a) She travels from the Earth to the nearest star system, Alpha Centauri, 4.300 light years (ly) away as measured by an Earthbound observer. How far apart are the Earth and Alpha Centauri as measured by the astronaut? (b) In terms of c , what is her velocity relative to the Earth? You may neglect the motion of the Earth relative to the Sun.

Δt
Alpha
Centauri
Earth
Lo
Lo
At
(a)
At,
Alpha
Centauri
(b)
Figure 28.11 (a) The Earth-bound observer measures the proper distance between the Earth and the Alpha Centauri. (b) The astronaut observes
a length contraction, since the Earth and the Alpha Centauri move relative to her ship. She can travel this shorter distance in a smaller time (her
proper time) without exceeding the speed of light.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions