Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.750 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?

Question
Asked Aug 26, 2019

Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.750 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?

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Step 1

From the given, 1 pint requires 36400 calories of energy to boil from room temperature.

0.750 pint requires, 

х аl
0.750pint
36400cal
1pint
x-0.750 pint36400cal
pint
x-27300 cal
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х аl 0.750pint 36400cal 1pint x-0.750 pint36400cal pint x-27300 cal

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Step 2

One calorie is equal t...

1000cal 4.184KJ
27300 cal 4.184KJ
1000 cal
114.22KJ
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1000cal 4.184KJ 27300 cal 4.184KJ 1000 cal 114.22KJ

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